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Oct13-09, 05:05 AM
HW Helper
P: 3,540
1) No the sum is [itex]-b/a=-(-p/1)=p[/itex] and the product is right.

2) You're right except for taking the sum as -p rather than p.

3) If we need p when the roots are unequal, how about we find the value(s) of p when the roots are equal, then take all other values?