View Single Post
gato_
gato_ is offline
#5
Nov19-09, 09:06 AM
P: 119
There is no standart way for those transforms. You have to proceed from the integral form:
[tex]\frac{1}{2\pi}PV \int_{-\infty}^{\infty}{exp(st)s^{-3/2}ds}=\frac{1}{2\pi}2\sqrt{t}\int_{0}^{\infty}{exp(z)z^{-1/2-1}dz}=2\sqrt{t}\frac{1}{2\pi}\Gamma[-1/2]=-2\sqrt{\frac{t}{\pi}} [/tex]
(for t>0)