Yeah, my bet! a, b are real numbers
I've constructed a linear function f: (0,1)>(0,2) defined by f(x)=2x
such that f(1/2)=1, when x=1/2 (mid point of domain), y=1 (mid point of range)
This linear function is certainly bijection, therefore (0,1)=(0,2)
But how to prove (0,1)=(a,b) where a, b are real numbers and a<b???
