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May16-10, 03:26 AM
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Quote Quote by AdamP View Post
I don't see how you got 1/2 d(v.v)/dt . after that v dot v is v squared magnitude, but how does that help me. dv/dt is a...
If you have an equation with a (like F = ma), you can dot it with v

then v.a = v.dv/dt = 1/2 dv2/dt, which is easy to integrate.