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Jano L.
Jano L. is offline
Feb17-12, 05:57 PM
P: 1,027
Hello qasdc,

I think one has to be careful here. When it comes to operators, there can always be some problem hiding there. Consider function [itex]H(p,q) = q + pq - qp[/itex]. I'm not familiar with this kind of differentiation, but your definition seems to give

\frac{\partial H}{\partial q} = 1 + p - p = 1.

But clearly [itex] pq -qp \neq f(p)[/itex].