Thread: Integration on operators View Single Post
 PF Gold P: 1,150 Hello qasdc, I think one has to be careful here. When it comes to operators, there can always be some problem hiding there. Consider function $H(p,q) = q + pq - qp$. I'm not familiar with this kind of differentiation, but your definition seems to give $$\frac{\partial H}{\partial q} = 1 + p - p = 1.$$ But clearly $pq -qp \neq f(p)$.