QFT S-matrix explanations are incomprehensible

In summary, in quantum field theory, scattering processes can be described using wavepackets or planewaves. Wavepackets are used when dealing with finite energy systems, while planewaves are used for systems with infinite energy. The S-matrix operator is used to calculate the scattering amplitude for planewaves, but it can also be used to describe the scattering of wavepackets by expanding them into a linear combination of planewaves. The linearity of quantum mechanics allows us to understand the scattering process by considering each plane wave separately. This concept can also be applied in nonrelativistic quantum mechanics.
  • #1
jostpuur
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TL;DR Summary
I've failed to understand S-matrix explanations. Does anyone feel like understanding them?
The first look at a scattering process is something like this: We define an initial state

[tex]
|\textrm{in}\rangle = \int dp_1dp_2 f_{\textrm{in,1}}(p_1) f_{\textrm{in,2}}(p_2) a_{p_1}^{\dagger} a_{p_2}^{\dagger} |0\rangle
[/tex]

Here [itex]f_{\textrm{in,1}}[/itex] and [itex]f_{\textrm{in,2}}[/itex] are wavefunctions that define some wavepackets that are about collide. Schrodinger equation will determine what happens, so we define an out state as

[tex]
|\textrm{out}\rangle = e^{-\frac{it}{\hbar}H} |\textrm{in}\rangle
[/tex]

If it turns out at that N particles fly out from the collision as some wavepackets, then something like

[tex]
|\textrm{out}\rangle \approx \int dq_1 dq_2 \cdots dq_N f_{\textrm{out,1}}(q_1) f_{\textrm{out,2}}(q_2)\cdots f_{\textrm{out,N}}(q_N) a_{q_1}^{\dagger} a_{q_2}^{\dagger}\cdots a_{q_N}^{\dagger}|0\rangle
[/tex]

is true. So far I feel like I understand what this all means. However, in the fully developed QFT the scattering is not handled like above. Instead we define an initial state as

[tex]
|\textrm{in}\rangle = |p_1,p_2\rangle = a_{p_1}^{\dagger} a_{p_2}^{\dagger} |0\rangle
[/tex]

So instead of wavepackets we wave planewaves that extend to infinities. Then we have an S-matrix operator that works so that it will give an amplitude for N particles flying out as

[tex]
\langle q_1, q_2,\cdots, q_N|S|p_1,p_2\rangle
[/tex]

What confuses me about this is that planewaves cannot really collide, can they? Wavepackets are something can actually collide, but planewaves are somekind of artificial tool? So how do you make the S-matrix operator work so that it makes the planewaves collide?

One formula for S-matrix is

[tex]
S = \lim_{t_{\textrm{B}}\to\infty} \lim_{t_{\textrm{A}}\to -\infty} e^{\frac{i}{\hbar}t_{\textrm{B}}H_0} e^{-\frac{i}{\hbar}(t_{\textrm{B}}-t_{\textrm{A}})H}e^{-\frac{i}{\hbar}t_{\textrm{A}}H_0}
[/tex]

It is nice that a formula exists, but I still don't understand that what calculations turn the wavepackets into planewaves.
 
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  • #2
jostpuur said:
What confuses me about this is that planewaves cannot really collide, can they?
Sure. Why not? Whether this has any nontrivial outcome depends on whether there's an interaction term in the total Hamiltonian.

jostpuur said:
Wavepackets are something can actually collide, but planewaves are somekind of artificial tool?
Wavepackets can be expressed as a linear combination of planewaves (as in Fourier theory).

jostpuur said:
I still don't understand that what calculations turn the wavepackets into planewaves.
If we can compute a general formula for the scattering of any (combination of) incoming planewaves into any combination of outgoing planewaves then we have a theory that can be compared with experiment.

One of the early chapters in Peskin& Schroeder has a section on how physically realistic beams (like in an accelerator) are modeled in these terms, and then how to compute scattering cross sections therefrom.
 
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  • #3
jostpuur said:
What confuses me about this is that planewaves cannot really collide, can they?
This is not necessarily related to QFT, the same issue arises also in nonrelativistic QM. I would suggest you to first try to understand it in this simpler context.

The crucial insight is the fact that QM is linear. So to understand how a wave packet scatters, you can expand the packet into plane waves and consider each plane wave separately. A nice analysis can be found e.g. in the book Bohm and Hiley, The Undivided Universe, Sec. 5.2.
 
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1. What is the QFT S-matrix?

The QFT S-matrix, or the quantum field theory S-matrix, is a mathematical tool used to calculate the probability of interactions between particles in quantum field theory. It is an important concept in understanding the behavior of particles and their interactions in the quantum world.

2. Why are QFT S-matrix explanations often considered incomprehensible?

QFT S-matrix explanations can be complex and difficult to understand because they involve advanced mathematical concepts and abstract theories. Additionally, the concepts of quantum field theory are inherently counterintuitive and can be challenging to grasp without a strong background in physics and mathematics.

3. Can anyone understand QFT S-matrix explanations?

While QFT S-matrix explanations may seem incomprehensible to those without a background in physics and mathematics, with dedication and effort, anyone can gain a basic understanding of the concept. However, a complete understanding of QFT S-matrix explanations requires a deep understanding of quantum field theory and advanced mathematical skills.

4. How can I improve my understanding of QFT S-matrix explanations?

To improve your understanding of QFT S-matrix explanations, it is important to have a strong foundation in physics and mathematics, particularly in quantum mechanics and quantum field theory. Additionally, studying and practicing with specific examples and problems can help clarify the concepts and make them more comprehensible.

5. Are there any resources available to help understand QFT S-matrix explanations?

Yes, there are many resources available to help understand QFT S-matrix explanations. These include textbooks, online lectures, and interactive simulations. It is also helpful to seek guidance from a knowledgeable mentor or tutor who can provide personalized explanations and answer any questions that may arise.

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