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nesan
nesan is offline
#7
Feb21-12, 08:30 PM
P: 67
Quote Quote by SammyS View Post
Well, those are incorrect.
(x + 1) (x2 - x + 1) = x3 + 1, not (x+1)3 .

(x + 1)3 = x3 + 3x2 + 3x + 1



Factor the x3+1 in the denominator.
x3+1 = (x+1)(x2 - x + 1)
Since the x3+1 in the denominator is cubed, that should give a factor in the denominator which cancels with (x+1)3 in the numerator.
Sweet, got it. Thank you very much. :)