Quote by SammyS
Well, those are incorrect.
(x + 1) (x ^{2}  x + 1) = x ^{3} + 1, not (x+1) ^{3} .
(x + 1) ^{3} = x ^{3} + 3x ^{2} + 3x + 1
Factor the x ^{3}+1 in the denominator. x^{3}+1 = (x+1)(x^{2}  x + 1) Since the x ^{3}+1 in the denominator is cubed, that should give a factor in the denominator which cancels with (x+1) ^{3} in the numerator.

Sweet, got it. Thank you very much. :)