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tiny-tim
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Mar7-12, 06:01 PM
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Free Body Diagram Finding Moments


Quote Quote by steve2510 View Post
ƩMb = (Fghcos26.57 x1.5 )+ (Fgbcos-36.87 x 1) +(2x5) -(2x21.25) = 0
shouldn't the moment of FGB about B be 0 ?

and the multiplier of FGH needs to be the distance from B to GH