View Single Post
Mar7-12, 06:01 PM
Sci Advisor
HW Helper
tiny-tim's Avatar
P: 26,148
Free Body Diagram Finding Moments

Quote Quote by steve2510 View Post
ƩMb = (Fghcos26.57 x1.5 )+ (Fgbcos-36.87 x 1) +(2x5) -(2x21.25) = 0
shouldn't the moment of FGB about B be 0 ?

and the multiplier of FGH needs to be the distance from B to GH