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It's because, in the normal way one uses a transformer, H decreases as µ increases, to keep B constant.
The point is that the primary winding sees B and the flux just as the secondary does. In a good transformer, the primary voltage makes the flux, with very little losses, and the secondary sees the same flux - except that they multiply it by their own numbers of turns.
Now if you have a very bad transformer which is inefficient at producing B and loses most primary voltage in the resistance of its copper windings, then H would be more constant than B, and µ would increase B and the secondary voltage.
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