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12Element
#1
Dec3-12, 04:03 PM
P: 3
Hello everybody,
First of all I want to thank you all for this great forum.

My question is if a superconductor inductor is charged with a certain voltage and then it is
open circuited what will happen.
My very basic understanding tells me that if the inductor is not a superconductor (it has
intrinsic resistance) the induced EMF will first accumulate opposite charges at each end
of the inductor and then the charges will move from the higher potential end to the lower
potential end in a decaying manner (a simple RL circuit) and all the energy will be dissipated
as heat due to the inductor intrinsic resistance, am I right?

And for a superconductor inductor, the same will take place however, the charges will remain
at each end (acting like a capacitor) storing the energy in the form of electric field as long as the temperature is low enough to maintain the superconductivity condition otherwise, the
law of conservation of energy will be broken because energy have nowhere to go, again am I
right?


Thank you again for all your efforts.

Regards.
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