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Dec3-12, 04:46 PM
PF Gold
phinds's Avatar
P: 6,514
First, you don't "charge" an inductor with a voltage, you do it with a current.

When inductors are "open-circuited" they spark across the gap as the circuit opens, with the energy of the spark equivalent to the energy in the inductor. Why would a superconducting inductor act any differently in principle?