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uart
#4
Nov18-05, 08:18 AM
Sci Advisor
P: 2,751
Is this right? e multipled out oddly...

Quote Quote by Pengwuino
oops yah i did... ill fix that
but is that true? I can't seem to grasp it... and its midnight so i dont think i will be able to easily realize whats going on
I was thinking that it should just be 3e^2t.... and I don't understand how it just got turned into e^4t
No, [tex]e^{2t} + 2 e^{2t}[/tex] would be equal to [tex]3 e^{2t}[/tex].
[tex]e^{2t} * 2 e^{2t} = 2 (e^{2t})^2 = 2 e^{4t}[/tex]

Or for an even more straight forward example,
x + 2x = 3x
x * 2x = 2x^2