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The meaning of Ionization |
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| Dec12-06, 09:23 AM | #18 |
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The meaning of IonizationLet's say I only include the strongest possible forces in a system. If what I do not include actually does make an effect, then my descrption of the system using what I started with will reveal "new" stuff that I could not account for. This is what I would call "new physics", something that I never accounted for with my description. For example, if I drop a ball from rest and only describe this using gravitational forces, then the dynamics of the ball should be completely described by the relevant forces. However, if I start doing this very carefully, and my ball has flaps, then I will notice that my description of the system isn't quite right. It didn't fall at the time that I expect it to. Why? Because the formulation that I used didn't take into account air friction in which, for this sytem and for the accuracy that I want, will now rear its effects that I can no longer ignore, which is not part of the description that I had. If I were ignorant about air friction in the first place, then this is "new physics" that I never realized before. That is what I asked for. If there truly are effects due to such overlap in system where the description of it completely ignored such effects, were are they? In a photoemission experiment, for example, where the resolution of the electron analyzers are getting to be extremely fine, where would the ignoring of any kind of overlap of the photoelectrons with the atoms in the cathode manifest it effects? Where would such effects reveal themselves in plasma physics? Note that it is not as if we don't know, or can't tell, when the approximation we make isn't adequate. The "free electron gas" model for a conductor, for example, is quite adequate to explain most of the behavior of an ordinary conductor, such as Ohm's Law. However, we also start seeing breakdown of this model under certain conditions, and for strongly-correlated electron systems, the "overlap" not only between electrons and ions of the solid, but also between electron-electron can manifest itself as a noticeable effects. This forces us to reformulate how we describe such a system, and take into account the necessary interactions. So yes, we do have experience in dealing with situation where our description is inadequate. In fact, that is what physicists do for a living. That is why I asked for where such a thing would occur and be observable already. Simply by pointing out that the mathematical description of coulomb's law is infinite in range is pointless when its presence cannot be detected or no longer relevant beyond a certain range. I asked for examples where such omissions DO make a difference. Zz. |
| Dec12-06, 10:08 AM | #19 |
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Here we go again. For physics, ionization is not, repeat not, rocket science. I mentioned above, ionization`is and has been understood for a very long time.(How about second semester of a first graduate level course in QM) And, surprise, classical physics does not play a role -- any more than it does in radioactive decay(which can produce ions)
For example, see Chapter 11, section 2.2, p 232 and on, in Mott and Massey's classsic, The Theory of Atomic Collisions, Oxford U. Press, 1933, Yes, 1933. They give a quite thorough discussion of ionization. Also see Linus Pauling's classic General Chemistry, 1947. If I was still teaching, I'd assign each student to find three references on ionization, and write a short paper thereon. I'd say end of story, except that ionization continued to be an important phenomena in cosmic ray physics, and particle physics prior to WWII, and even through the early 1950s. Why? (There are famous pieces of equipment used then and now that might be related to ionization......) Those who neglect history are, in physics, very likely to get things wrong. If there's one thing that bothers me about many posts in this Forum, it is a remarkable ignorance of science history, with elaborate discussions about things that are clearly discussed in the literature. With all due respect, this thread is a good example of what I'm talking about. Sorry 'bout that. Regards, Reilly Atkinson By the way, just for completeness, an ion is an atom with net non-zero electric charge. Why, every time you breath you take in a few ions -- what kind? |
| Dec12-06, 10:15 AM | #20 |
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So I guess that the wave-functions overlap, but the contribution towards any effect are neglible in practice? I apologise if I am ignorant of the history of Physics, I am mostly self-taught and most of the literature I have access to is online... so you are most probably correct that I am ignorant in that respect. Still, I felt that the original question from the original post was perfectly valid... regardless as to what the history of a subject is or how well documented it is, that doesn't change the validity of a question, nor the fact that nobody gave a simple answer. |
| Dec12-06, 10:53 AM | #21 |
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This is why I asked, if our description of free particles as unbound, continuous states is inaccurate due to some "overlap" or influence from the original atom, then were would this manifest itself? To simply say something is too small that it simply can't be detected is, frankly, irrelevant. Zz. |
| Dec12-06, 11:31 AM | #22 |
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At lower energies, the computations get tricky because the problem becomes a three-body scattering one-- that is, here, with two particles in the final state -- sometimes the issue is termed "final state scattering". It's a good first year QM problem, at least in the Born approximation -- the initial state is bound electron + nucleus + incident particle --> nucleus + electron + scattered incident particle. You can get reasonable estimates of the probability with a damped exponential wave function for the bound electron, and standard plane waves for the initial and final particle and the outgoing electron. (Just to be clear, to take into acount the "left proton" you must use continuous Coulomb wave functions. A good exercise -- at what energy does the use of a plane wave, rather than a coloumb one, make less than a 5% error in the Born approximation?) An ionized hydrogen atom is our old friend, the proton. And, the description of ionization in QM is perfectly straightforward -- as I mentioned above, we've had 70+ years to deal with any ambiguities in the basic description of ionization. This is not to say that we know everything about the process, but what we don't know has, so far, failed to cause any problems. Remember that, for example, both the mu and pi mesons were discovered by means of ionization processes -- what was the experimental equipment involved? Regards, Reilly Atkinson |
| Dec13-06, 07:18 AM | #23 |
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I have another two problems concerning ionization.
First, has the physical mechanism of non-sequential ionization been understood clearly? Second, I must point out the Coulomb kind of force is totally unique because V(r)~1/r. Maybe when V(r)~1/r^(1+$) (where $>0 is some small real number), the physical picture is much clearer. Think about it, when the main quantum number n of hydrogen is 100, the radius of the electron is 0.53 micrometre and the energy is -1.36 milli-eV. Is the hydrogenic Rydberg atom just a proton with an ionized electron? Quantum River |
| Dec13-06, 07:28 AM | #24 |
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Secondly, under what condition do you often get a hydrogen atom in an excited n=100 state? I mean, since you are so focused on such high quantum number already, why don't you figure out how EXACT it is to get to that particular state AND how far away is the vacuum level! Thirdly, what does a small variation in the coulomb force have any relevance here? Adding an infinitesimal term to the coulomb force would make a difference to an electron that's a meter away from the ionized atom? Furthermore, what exactly is the point in such a hypothetical scenario in the first place? And what is so unique about it? A gravitational potential also has a 1/r dependence! Zz. |
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