Net Ionic equation

tylernichols

Can anyone help me through this net ionic equation problem?

Pb(ClO4)2 (aq) +NaI (aq) -> PbI2 (s) + NaClO4 (aq)

Snazzy

Pb+2 + ClO4- + Na+ + I- -> PbI2 (s) + Na+ + ClO4-

ClO4- and Na+ cancel out on both sides of the equation, so you're left with

Pb+2 + I- -> PbI2 (s)

chemisttree

Just make sure that you have the same number of Pb, ClO4, Na and I on both sides of the equation. In your example above, there is one I on the left and two on the right, for example. Same goes for ClO4....

Snazzy, check your work before you post.