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| Feb14-09, 12:10 AM | #1 |
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#8
1. The problem statement, all variables and given/known data
A point charge mass of 0.0788kg and q charge= +6.62 uc is supended by a thread between the vertical plates of a parallege capacitor. If the angle of delflectionis 23.7 degress and the seperation between the plates is d= 0.0242m, whats the potential energy? 2. Relevant equations v=w/q 3. The attempt at a solution not sure, where to begin but.... V= w/q w=1/2cv sq F= keqq/r F= 8.99e9 (6.62e-6)/.0242 sq |
| Feb14-09, 12:30 AM | #2 |
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I think you'll need to draw a picture here.
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| Feb14-09, 12:33 AM | #3 |
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i have 2 parallel lines then the distance btw the lines is d= .0242, then a pendulum ball @ an angle
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| Feb14-09, 12:35 AM | #4 |
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#8 |
| Feb14-09, 12:37 AM | #5 |
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there isnt it only tells u the angle and the distances btw the 2 parallel lines
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