#8


by xswtxoj
Tags: None
xswtxoj
xswtxoj is offline
#1
Feb14-09, 12:10 AM
P: 87
1. The problem statement, all variables and given/known data

A point charge mass of 0.0788kg and q charge= +6.62 uc is supended by a thread between the vertical plates of a parallege capacitor. If the angle of delflectionis 23.7 degress and the seperation between the plates is d= 0.0242m, whats the potential energy?
2. Relevant equations
v=w/q


3. The attempt at a solution
not sure, where to begin but....
V= w/q
w=1/2cv sq
F= keqq/r
F= 8.99e9 (6.62e-6)/.0242 sq
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LowlyPion
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#2
Feb14-09, 12:30 AM
HW Helper
P: 5,346
I think you'll need to draw a picture here.
xswtxoj
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#3
Feb14-09, 12:33 AM
P: 87
i have 2 parallel lines then the distance btw the lines is d= .0242, then a pendulum ball @ an angle

LowlyPion
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#4
Feb14-09, 12:35 AM
HW Helper
P: 5,346

#8


Quote Quote by xswtxoj View Post
i have 2 parallel lines then the distance btw the lines is d= .0242, then a pendulum ball @ an angle
What's the length of the pendulum?
xswtxoj
xswtxoj is offline
#5
Feb14-09, 12:37 AM
P: 87
there isnt it only tells u the angle and the distances btw the 2 parallel lines


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