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Age of the universe from a photons point of view |
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| May14-10, 05:53 AM | #1 |
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Age of the universe from a photons point of view
if time has no meaning for a photon, do you think its correct to say that from its point of view that age of the universe is 0 seconds?
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| May14-10, 06:07 AM | #2 |
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This would seem more of a philosophical question than a physics question. |
| May14-10, 09:42 AM | #3 |
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If the "material" universe is fundamentally vibrations void of a core substance that vibrates, can the universe be said to exist at all? Which begs the question: What or who am "I"?
What is there that really, really exists? Is this not the same fiery question that both physicists and philosophers dance around? I feel your question is a meaningful one. Especially if we direct such inquiries toward our own sense of being, rather than to a photon or thing that is seemingly external. |
| May14-10, 09:53 AM | #4 |
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Age of the universe from a photons point of view
thnka you for saying my question is meaningful, Im really sorry that i dont feel i can return the favour. Supposing string theory is true , a big suppose, and everythign is made of vibrating strings , why would that imply the universe doesnt exist?
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| May15-10, 12:56 AM | #5 |
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| May15-10, 01:20 AM | #6 |
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| May15-10, 01:20 AM | #7 |
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| May17-10, 04:05 PM | #8 |
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It is said that the grand total of all positive and negative forms of energy are equally balanced within the universe so that the sum = 0. This is why the universe can arise from nothing. It is a perfect child that needs no other, no parents. The phenomenal universe doesn't exist; there is no solid out there, out there; it only appears that there is; and that's good enough. |
| May17-10, 04:45 PM | #9 |
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| May17-10, 04:52 PM | #10 |
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What physicists generally do is to come up with some agreement about what certain terms mean and that allows you to make some falsifiable statements about the universe. Rather than debate what "existence" really means, you come up with a definition, and then run with it. If you define "exists" as meaning "eats spinach and likes the color blue", then the universe does not exist. If you don't like that definition of "exists" then come up with one. |
| May17-10, 04:59 PM | #11 |
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And how is this to be thought about? Did the photon grow colder on its journey or was it always (taking the timeless view) that cold? |
| May17-10, 08:10 PM | #12 |
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This picture is relatively obvious if you consider the simpler case of just the doppler effect, where it's not as if the photon wavelength has actually changed, just that the motion of the source makes it so that each subsequent peak of the wave is closer or further apart than you would normally have. |
| May18-10, 02:35 AM | #13 |
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So given that, do we want to say that the photon started out its journey blue and gradually turned red (a wavicle view)? Or do we want to say that the photon exists over the whole of the path in timeless fashion and so was in fact the same colour all along? The first view says there is change actually happening along the way, the second that the photon always had one temperature. I ask really because I can't decide how much to take photons as "real" particle exchanges rather than just quantum sum over histories that equilibrate between two locations at different spacetimes. In one view, something travels and is changed. In the other, there is just a path that crystalises to connect locations. |
| May18-10, 02:55 AM | #14 |
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I really dont see the point. Time is meaningless from a photon's perspective.
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| May18-10, 03:21 AM | #15 |
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Why does the photon not see it? Because it was always red? Or just did not notice itself turning red? |
| May18-10, 03:48 AM | #16 |
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The photon can't 'see' anything, because as Chronos correctly points out, time is meaningless to the photon. As far as the photon is concerned, it's exactly as you point out: an exchange of a particle between emitter and absorber. That is to say, there isn't any clear distinction between a virtual particle and a real particle. A real particle is generally considered to be a particle that is on its "mass shell". Well, when you consider an exchange of photons between two charged particles, the mass of the virtual particle that is exchanged asymptotically approaches zero as the distance between the two charged particles becomes large.
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| May19-10, 04:13 PM | #17 |
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