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| Jun21-09, 11:54 AM | #1 |
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calculus calculator
Wolframalpha.com is a really good one. It looks like a search engine, and to find the derivative, type in d/dx(function.) To do antiderivatives, you need the symbol ∫. For limits use lim(function) as x->whatever.
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| Jun21-09, 12:05 PM | #2 |
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I found some errors in it doing simple antiderivates.
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| Jun21-09, 03:34 PM | #3 |
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For antiderivatives you can just type "antidifferentiate f(x) dx" or "integrate f(x) dx"
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| Jun27-10, 01:01 PM | #4 |
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calculus calculator
Wolfram is generally reliable, Although it often generates solutions that have been simplified in a very strange manner. I find it to be a useful for double checking my work. For indefinite integrals, possible solution pathways are also provided. If you get a question wrong, these usually help pinpoint the problem, Although I'd never completely rely on it. I have always considered it a supplementary tool I can use to verify my knowledge and confidence, nothing else.
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| Jun27-10, 01:06 PM | #5 |
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| Jun27-10, 01:29 PM | #6 |
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| Jun27-10, 06:48 PM | #7 |
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| Jun27-10, 07:53 PM | #8 |
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either way I don't remember exactly the problem(s), but yeah I did find some error(s). |
| Jul13-10, 09:27 AM | #9 |
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I've just checked this calculator for the partial differentiation of ((x1-m1)^2/s^2) w.r.t 'm' i.e. d/dm(((x1-m1)^2/s^2))
and the result was (-2 (-m1 + x1)^2 s'[m])/s^3 + (2 (-m1 + x1) (-m1'[m] + x1'[m]))/s^2; I'm still confused how do we differentiate a function containing 'm1' w.r.t 'm'; m is a 2D variable which consists of (m1,m2). Can please somebody explain this to me. I'll be really very grateful. |
| Jul14-10, 06:10 AM | #10 |
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Wolfram alpha doesn't know that m is a 2d variable consisting of (m1,m2). SInce you differentiated an expression by m, and the expression doesn't contain m (only x1, s, and m1), it assumes that all three of x1, m1, and s are functions of m, and gives you the derivative using that assumption.
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| Jul14-10, 06:46 AM | #11 |
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Thank you very much for your reply. Can u tell me how to solve my equation in general or through the calculator?
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| Jul14-10, 03:35 PM | #12 |
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It depends what you are trying to do. You might want to read up on vector calculus - I suggest starting with:
http://en.wikipedia.org/wiki/Vector_calculus Do you want the gradient of the scalar function f=((x1-m1)^2/s^2) ? In this case, since f is independent of m2, it would just be df/dm1*e1, where e1 is the unit vector in the m1 direction. What problem are you trying to solve exactly? |
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