
#1
Sep2010, 08:12 PM

P: 2

Suppose, i want to diagonalize operator A by matrix S (A'= S^\\dagger A S). Do i need to form S from "NORMALIZED" eigenvectors? I checked and found that even S formed from notnormalized eigenvectors works.




#2
Sep2010, 10:50 PM

P: 546

If S isn't normalized, you will get a diagonal matrix. However, the diagonal elements of the matrix will not be the eigenvalues of A.



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