Originally Posted by Chronos
Yes, but,I am reluctant to give any numbers fearing how they might be abused. Oh well.. It takes some pretty impressive accelerations to generate much of an effect. 1 degree K requires about 2.4E22 cm/s^2. For a temperature of 2.7K, which is what I was curious about, this works out to roughly 7E19 G... [ducking for cover now]. I thought this might somehow relate to the maximum mass of a detectably 'radiating' black hole, but, that is a pretty speculative approach.
Measuring this experimentally is, however, quite the technological challenge. I've heard some proposals involving high energy lasers, but, not about it having yet been tried.
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Chuckle. Have i been scolding you about numbers? If I did I am sorry. There is no need to duck for cover!
actually I heard of some experiment at Stanford SLAC around year 2000 IIRC or 2001. But I lost the link to it. I dont know if it was a good experiment.
I vaguely remember that if G=hbar=c=k=1 then the formula for the temperature is
T = a/2pi
I will assume your number is right, as a guide to me in trying to remember.
I know that 1.4 kelvin is E-32
(they have planck temperature listed with the other constants at NIST)
so one would just multipy that by 2pi to get the acceleration that would produce that temp.
2pi E-32
this acceleration will produce 1.4 kelvin.
It looks like I am done but if I want to interpret that acceleration in metric terms then I have to know that the unit of acceleration (G=c=hbar=1) is 5.56E51 meter per second per second (again from the NIST figures for planck time and length etc.)
so multiplying by 2piE-32 gives 35E19 meter per second per second.
Wow! I get around the same answer you do! I get 3.5E20 meters which is 3.5E22 cm persecondpersecond. It is the right OOM (order of magnitude)
I happened to be calculating 1.4 kelvin while you were doing 1.0 kelvin but we dont worry about trivial details!
So maybe i remembered right and Unruh formula for temp is really
T = a/2pi
but I'm still unsure and need to check this---earlier remembered something different for the denominator