Is the force on a moment/torque carried?

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Discussion Overview

The discussion revolves around the concept of moments and torque in the context of applying force to a door. Participants explore how the distance from the pivot affects the moment generated by a force and the relationship between force and distance in this scenario.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether the moment remains constant at different points along the door, suggesting that if the moment is 100 Nm at 10 meters, it should also be 100 Nm at 5 meters, leading to confusion about the corresponding force.
  • Another participant asserts that if the force is fixed, the torque decreases as one moves closer to the hinge, implying that the door becomes harder to push with the same force.
  • A participant seeks clarification on the relationship between the force applied at different points and the resulting moment, indicating a lack of understanding of how moments are distributed along the door.
  • One participant explains that applying a constant force closer to the hinge results in a lower moment, and to achieve the same moment at a shorter distance, a greater force would be required.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between force, distance, and moment. There is no consensus on how moments are perceived at different points along the door, and the discussion remains unresolved regarding the interpretation of these concepts.

Contextual Notes

Participants' statements reflect varying assumptions about the nature of moments and the effects of distance from the pivot, with some relying on intuitive reasoning rather than mathematical proofs.

Illusion3
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Hello,

I had an interesting thought about how moments work, and if the force is carried.

If I am pushing on the handle of a door, say 10 metres away from the pivot, a force of 10 Newtons, the total moment would be 100nm.

Does this mean that at every point of the door, half way for instance, the moment will be the same? Say for instance at the point 5 metres from the pivot, can you say that the moment at that point is also 100nm, and thus the force must be 50 Newtons? This makes no sense, as the force applied 1cm from the pivot would be 1000 Newtons.

Albeit what my teacher told me, I believe that if you half the distance from where you push, the force will also be halved, and thus the moment quartered, although I have no mathematical proof.

Thanks for your help!
 
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Hello Illusion3! :smile:

i'm not sure i follow you :confused:

if the amount of force is fixed, then the torque gets less as you get nearer the hinge …

the door is harder to push, in the sense that it moves slower for the same force

alternatively, if you push with the same moment, then the amount of force you need is increased as you get nearer the hinge
 
Thanks for your reply,

I think my question is a little confusing. Please look at the following attachment that should display the diagram about my question.

In other words, the diagram shows that if I apply a force at the top, obviously half way in the middle there is also a moment, although my hand doesn't push at that area. What would the force be half way in the middle?
 

Attachments

Illusion3 said:
In other words, the diagram shows that if I apply a force at the top, obviously half way in the middle there is also a moment, although my hand doesn't push at that area. What would the force be half way in the middle?

Sorry, I have no idea what you mean. :confused:

A moment of what about what?
 
Easy.

If you apply 10 Newtons 10 meters away from the hinge, it's 100 Nm (since you do 10x10)

If you apply 10 Newtons 5 meters away from, it'd be 50 Nm that you're applying (since you do 10x5)

So, the closer you get to the hinge, provided you're applying a constant force, the moment will decrease. That's why you never push a door to open it close to the hinge.


If you want the moment to equal 100 5 meters away from the door, you'd need to apply 20 Newtons (since you do 20x5)

Hope that helps,

-Dory
 

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