Limits with Square roots Question help


by Sleighty
Tags: calculus, cos x, limit, limits, square roots
Sleighty
Sleighty is offline
#1
Apr9-11, 06:09 AM
P: 5
1. The problem statement, all variables and given/known data

lim x -> infinity : sqrt(x^2 + 4x(cos x) ) - x

find the limit (or lack there of)

2. Relevant equations

look above

3. The attempt at a solution

ok so i used the addition/subtraction law to show that the limit of f(x) = - x as x --> infinity = infinity

now for the other half of the function, i cant seem to find out how to mathematically prove that there is no limit. logically i can tell that there is no limit because COS X has no limit.

can someone explain how i prove this mathematically?
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HallsofIvy
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#2
Apr9-11, 06:28 AM
Math
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Thanks
PF Gold
P: 38,886
You are completely wrong about this problem- you cannot use the "addition/subtraction" law here because you cannot add/subtract "infinity".

Think of this as the fraction
[tex]\frac{\sqrt{x^2+ 4x}- x(cos(x))}{1}[/tex]
and "rationalize the numerator"- multiply numerator and denominator by
[tex]\sqrt{x^2+ 4x(cos(x)}+ x[/tex].
Sleighty
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#3
Apr9-11, 06:29 AM
P: 5
thanks mate :) im pretty noob at calculus. :(

EDIT: what happened to the cos x in the equation?

Sleighty
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#4
Apr9-11, 06:42 AM
P: 5

Limits with Square roots Question help


bump
HallsofIvy
HallsofIvy is offline
#5
Apr9-11, 07:16 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,886
Sorry I accidently dropped it. I have edited my previous posts:
Multiply numerator and denominator by
[tex]\sqrt{x^2+ 4x(cos(x)}+ x[/tex].
Sleighty
Sleighty is offline
#6
Apr9-11, 07:25 AM
P: 5
Hi, thanks for correcting that mistake, but should i apply L'Hopitals rule in this case? i cant tell :(


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