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Need help using Ion Electron Method in acidic conditions. 
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#1
Oct2611, 10:20 PM

P: 9

Using the Ion Electron Method (acidic conditions) I need to solve:
MnO_{4}^{} + C_{2}O_{4}^{2} > Mn^{2+} + CO_{2} So I tried doing: MnO_{4}^{} > Mn^{2+} And: C_{2}O_{4}^{2} > CO_{2} + 2H_{2}O Then I balanced the oxygen atoms with H_{2}O MnO_{4}^{} > Mn^{2+} + 4H_{2}O And: C_{2}O_{4}^{2} > CO_{2} + 2H_{2}O Then I added the hydrogen atoms: MnO_{4}^{} + 8H^{+} > Mn^{2+} + 4H_{2}O And: C_{2}O_{4}^{2} + 4H^{+} > CO_{2} + 2H_{2}O Then I tried balancing the electrons and I got 3e for the first equation and 2e for the second. Then I tried combining the two: 2MnO_{4}^{} + 16H^{+} + 3C_{2}O_{4}^{2} + 12H^{+} > 2Mn^{2+} + 8H_{2}O + 3CO_{2} + 6H_{2}O Cancel out the H^{+} and H_{2}O: 2MnO_{4}^{} + 28H^{+} + 3C_{2}O_{4}^{2} > 2Mn^{2+} + 14H_{2}O + 3CO_{2} I don't know if there is something else I should do (which I suspect there is but I can't tell), and I think I am doing something wrong because my answer didn't turn out right. Any help would be appreciated. 


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