
#1
Nov2611, 11:37 PM

P: 1,011

A centrifuge is used to increase the sedimentation rate of
particles suspended in a liquid, over the rate produced by gravity alone. Find the angular velocity of a centri  fuge in which a particle 10.0 cm from the axis of rotation experiences a radial acceleration of 1.00* 10^3 times gravitational acceleration g. Solution: radius (r) = 0.01 m ; a_{r} = 1.00*10^3*9.80 1.00*10^3*9.80 = (.01)w^2 w = ( 1.00*10^3*9.80/.01)^(1/2) = 989 Answer is 313 rad/sec.... where did I go wrong>? 



#3
Nov2711, 12:18 AM

P: 1,011

thank you,



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