How well has the force of Dark Energy been calculated?by LuckyNate Tags: calculated, dark, energy, force 

#1
Jan312, 11:59 PM

P: 20

What i would like to know is, how far apart would 2 masses of 1kg each have to be, for the effects of their gravitational attraction to be overcome by the force of the Dark Energy (i.e. to begin moving away from, rather than toward one another?)
The basic question I am trying to pick away at is, does the dark energy have a force that is gravity like (somehow affected by the square of or square root of distance) or does it just add up over distance? also is there going to be some sort of threshold or horizon out there at a certain distance from a mass where the dark energy is somehow pushing against the edge of its gravitational field (if my assumption that the empty space is pushing out against anything with mass is correct)? 



#2
Jan412, 12:17 AM

P: 38

Dark energy is an attempt to explain why our exploded big bang universe is undergoing an accelerated expansion.
An other attempt is that our big bang universe is surrounded by similar big bang universes, and those pull by gravity on our big bang universe, explaining why ours has and accelerated expansion. 



#3
Jan412, 12:21 AM

P: 20





#4
Jan412, 12:26 AM

P: 38

How well has the force of Dark Energy been calculated? 



#5
Jan412, 12:33 AM

P: 20

vox they are not the same...gravitation is inherent in mass, and curves the surrounding spacetime...the dark energy appears to be an inherent energy present in the empty spacetime itself, the question i need answered is 'how strong is the dark' energy and 'how its force plays out (is it analogous to magnetism, gravitation, etc.)' If you cant directly give an answer to this question or at least confirm that the answer is not yet known, then please dont reply.




#6
Jan412, 12:33 AM

P: 126

The expansion of the universe adds up over distance, at a rate of 73.8 kilometers per second per megaparsec.
Gravity overwhelms expansion out to a distance of about 200 million light years, the size of the Local galactic supercluster. I once ran a calculation on the expansion rate between the earth and moon, if gravity was ignored, and I got a rate of a tenth of a diameter of a proton per second. It's astounding weak, but since it's additive with distance, and there's so much distance, there's an awful lot of expansion going on. 



#7
Jan412, 12:38 AM

P: 38





#8
Jan412, 12:45 AM

P: 20

if so, would the limiting distance be smaller for smaller masses? can we try the math? 2 masses of 1kg each are touching in open space...how far apart will i have to pull them before they stop attracting due to gravitation and begin moving apart due to dark energy? will there be a distance at which the 2 forces (gravitation and dark energy) are totally balanced? if so what is that distance? 



#9
Jan412, 12:56 AM

P: 38

It really depends how your 2 1kg masses are placed relative to the proximity of 2 black holes with largest local attraction. 



#10
Jan412, 01:06 AM

P: 20





#11
Jan412, 01:37 AM

P: 126

I've found a figure for the strength of Dark Energy given as 2 x 10^35 m/s^2.
Plug that into F = G(m1m2/r^2) as F, G =6.674 x 10^11, m1 and m2 are both 1, and I get a figure of 3.3 x 10^12 meters or .00036 light years. I think its in the ball park. 



#12
Jan412, 02:36 AM

P: 20

just about 3:08 light hours away...wow that means cosmological 'empty spaces' have to be immense for even the smallest effects of the dark energy to be felt.
Sadly, this doesnt make it much easier for me to wrap my head around, I was hoping for a more grassroots number like, "The distance from New York to Chicago" or something. With these kinds of numbers even the smallest mass overpowers the dark energy easily, makes one wonder how clean is the empty space after all? It must be incredibly empty for the gravity to not overtake it with ease, because apparently even the smallest masses can overcome it gravitationally, even over great distances. 



#13
Jan412, 03:51 AM

P: 38

That would all be true if space was empty, but it is not ...




#14
Jan412, 04:28 AM

P: 20

At no point in your rambling, incoherent response, were you even close to anything that could be considered a rational thought. Everyone in this room is now dumber for having listened to it. I award you no points, and may God have mercy on your soul." I think you are missing the point of this discussion. The main core of what I was trying to get at was "In terms that a regular person can grasp, how strong is the Dark Energy?" I think that question was well and thoughtfully answered by alexg (thanks alexg) and if more people spent their time trying to help others learn in this way we could all benefit. 



#15
Jan412, 04:34 AM

P: 499

Assuming that it means 2 x 10^35 s^2 gives r^3=6.674 E11/2E35 =3.33E+24, so r=1.5E8 metres  half a light second. 



#16
Jan412, 04:50 AM

P: 20

Your numbers indicate that at about one third the distance from earth to the moon, two 1kg masses will stop attracting and balance out the force of gravity versus the expansion...this sounds like a more reasonable figure to me, one that allows the force of gravity to be overpowered by the expansion at believable distances between dust particles and gas atoms floating around in space but also makes the expansion seem stronger than i thought originally. Here we have another thoughtful answer given by an informed council. Thanks Chronon. Can anybody else throw their 2 cents in? which of these estimates is closer? 



#17
Jan412, 05:34 AM

P: 126

I like Chronon's numbers better myself. When I tried to use 10^40 kg for both m1 and m2 (estimated the mass of two galaxies), I got a figure for r that was waayyyy too high.
One question I have though is why is it r^3, and not r^2? 



#18
Jan412, 05:34 AM

P: 38

The answer given here to your question is correct in your thought experiment conditions. 


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