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Derivation of Pogson's law |
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| Feb3-12, 08:42 AM | #1 |
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Derivation of Pogson's law
Hello i am strugling to derive Pogson's law, i feel i am soo close, but i am not there yet. Here is what i ve done soo far.
\begin{equation} \begin{split} j_6 \cdot 100 &= j_1\\ \frac{j_6}{j_1} &= \frac{1}{100}\\ \frac{j_6}{j_1} &= 10^{(-2)}\\ \frac{j_6}{j_1} &= 10^{-0,4\cdot 5}\\ \frac{j_6}{j_1} &= 10^{-0,4\cdot (m_6 - m_1)}\\ \frac{j_1}{j_2} &= 10^{-0,4\cdot (m_1 - m_2) }\\ \frac{j_1}{j_2} &= 10^{-0,4\cdot (m_1 - m_2) }\\ \frac{j_1}{j_2} &= 2,5^{-(m_1 - m_2) }\\ \log_{10} \frac{j_1}{j_2} &= \log_{10} 2,5^{-(m_1 - m_2) }\\ \log_{10} \frac{j_1}{j_2} &= -(m_1 - m_2) \cdot \log_{10} 2,5\\ (m_1 - m_2) &= -\frac{\log_{10} \frac{j_1}{j_2}}{\log_{10} 2,5}\\ \end{split} \end{equation} What am i missing??? |
| Feb3-12, 10:05 AM | #2 |
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I allready got it. TY
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