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The protom fluxby nykon
Tags: flux 
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#1
Feb1412, 02:44 AM

P: 7

Dear forum users,
I have a quite simple question. I have got a flux of protons measured in 1/(cm^2 s sr), I would like to have it in 1/(cm^2 s). Best regards, nykon 


#2
Feb1612, 03:00 PM

P: 1,261

Then you should multiple by the number of sr



#3
Feb1712, 08:12 AM

P: 7

My answer would be: The area of the sphere with radius of 1m^2 is: [itex]S = 40000 \pi [cm^2][/itex] the effectiv area of the detector is D = 1cm^2, so: [itex]\frac{D}{S} = \frac{1}{40 000 \pi} = \frac{1}{125600} = 7.9 \times 10^{6} [/itex] So the soild angle of my detector should be: [itex]θ_{D} = 4\pi \times 7.9 \times 10^{6}[sr][/itex] So finally: [itex]θ_{D} = 9.92 \times 10^{5} [sr][/itex] Am I right? Best regards, nykon 


#4
Feb1712, 10:06 AM

P: 1,261

The protom flux
Yeah, I think that looks great!



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