
#1
Feb1812, 03:59 PM

P: 241

According to Slater determinant, can one say that two bosons are able to place in the same position X , but two fermions can not, no matter what their states are?




#2
Feb1812, 04:35 PM

Sci Advisor
Thanks
P: 3,864

It's the total wavefunction that must be antisymmetric. This includes both the position and the spin (and any other degrees of freedom that may be present, like isospin). So for example a spin up fermion and a spin down fermion can have the same X.




#3
Feb1812, 04:49 PM

P: 241

Thanks for replying, but According to Slater determinant when X1=X2 the antisymmetric wave function become zero.




#4
Feb1912, 10:42 AM

Sci Advisor
Thanks
P: 3,864

Pauli Exclusion Principle
You're mistaken, hokhani. Since you don't believe me, take a look at the Slater Determinant page in Wikipedia. There it says, "The Slater determinant arises from the consideration of a wave function for a collection of electrons, each with a wave function known as the spinorbital, χ(x), where x denotes the position and spin of the singular electron."
Your reference may be doing the same thing: letting the notation x stand for both spin and position combined. 



#5
Feb1912, 12:13 PM

P: 241

Thanks very much
As i found out, there are 3 factors determining the pauli exclusion principal: 1) Particles' positions(x,y,z) 2) Particles' spins 3) Particles' energy states Would you tell me if i am wrong? 



#6
Feb1912, 07:03 PM

P: 198

If scientists have entangled more than two fermions, would that violate the principal?




#7
Feb2012, 03:18 PM

P: 241

Excuse me; I was wrong
In fact the third part covers the two other parts. 


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