|Feb23-12, 09:11 PM||#1|
Reactions of Halogens with Metals
To test the ability of Br2 and I2 to oxidize copper metal, the reactions take place between Br2water and I2 solution with copper:
Cu (s) + Br2 (aq) -> Cu2+ (aq) + 2Br- (Aq)
Cu(s) + I2 (methanol) -> Cu2+ (methanol) + 2I- (methanol).
Write the net ionic equations describing the results of these two experiments.
I believe that the Cu (s) should oxidize, and thus color change. Particularly with Br2 water (bromide water), so I recorded the net ionic equation as 2Cu (s) + Br2 (aq) -> 2CuBr(s)
However, I'm unsure if this is correct or what to do with the second equation.
Has anyone ever done these reactions or know them off hand? Is it possible that a precipiate could form between Cu2+ and I2?
|Feb24-12, 01:52 AM||#2|
Why not CuI?
Actually I am sure about CuI, but I am not convinced you will get CuBr and not CuBr2.
|Feb24-12, 05:50 AM||#3|
The lab notes predict Br2 reduces to Br2-, hence my writing CuBr
|chemistry 102, electrochemistry, oxidation, reduction|
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