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Limit of ln as x goes to infinity 
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#1
Mar712, 10:25 PM

P: 41

1. The problem statement, all variables and given/known data
lim (lnx)^2/x x>infinity 2. Relevant equations none 3. The attempt at a solution =5lnx/x * (1/lnx)/(1/lnx) =5/(x/lnx) How do I calculate x/lnx? 


#2
Mar712, 11:37 PM

HW Helper
Thanks
P: 10,344

ehild 


#3
Mar712, 11:40 PM

Mentor
P: 21,216

Also, since you haven't taken the limit yet, you should not get rid of the "lim" symbol. 


#4
Mar812, 12:12 PM

P: 99

Limit of ln as x goes to infinity
what you typed is equivalent to: [tex]\displaystyle \lim_{x\to \infty}\dfrac{[ln(x)]^2}{x}[/tex] Did you intend [tex]\displaystyle \lim_{x\to \infty}[ln(x)]^{\frac{2}{x}} \ ?[/tex] 


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