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goldfish9776
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Homework Statement
my ans is lnx = (-1/y) + c
(-1/y) = lnx -c
y = -1/ (lnx -c ) , but the answer given is (-1/ln x )+ C , how to get the answer given ?
When you post a question, please put the problem statement into the first section, not the thread title.goldfish9776 said:Homework Statement
my ans is lnx = (-1/y) + c
(-1/y) = lnx -c
y = -1/ (lnx -c ) , but the answer given is (-1/ln x )+ C , how to get the answer given ?
Homework Equations
The Attempt at a Solution
The notation "Dy/dx" represents the derivative of the function y with respect to x. In other words, it represents the rate of change of y with respect to x. The expression "(y^2)/x" is the function that is being differentiated, and it is equal to the derivative of y with respect to x.
To determine the general solution of this differential equation, we need to separate the variables and integrate both sides. This involves bringing all terms with y to one side and all terms with x to the other side. Then, we can use the power rule for integration to solve for y. The result will be the general solution, which includes a constant of integration.
One example of a specific solution to this differential equation is y = 1/x. This solution satisfies the equation because when we substitute it into the equation, we get the statement "1/x = (1/x)^2/x", which is true.
The "D" in "Dy/dx" stands for "derivative." It represents the operation of finding the rate of change of a function with respect to its independent variable. In this context, it is used to denote that the equation is a differential equation, which involves derivatives.
This differential equation is commonly used to model exponential growth and decay processes, such as population growth or radioactive decay. It can also be used to describe the flow of fluids and the behavior of electrical circuits. In general, any situation that involves a quantity changing at a rate proportional to its current value can be modeled by this type of differential equation.