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stationary electron broglie wavelength |
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| Mar11-12, 04:46 AM | #1 |
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stationary electron broglie wavelength
de broglie's formulation:
λ=h/(mv) the more the momentum of a particle, the less wave-like behaviour it shows. But what if we have electron which is stationary, i.e. zero speed, according to formula λ becomes ∞. What does this mean? Does the electron disappear? |
| Mar11-12, 08:04 AM | #2 |
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From the viewpoint of the Schrodinger equation, the orbital angular momentum of the hydrogeh-like atom in the ground state is zero. But this does not mean that the electron velocity is zero due to uncertainty principle. Uncertainty in the position of the electron is of the order size of an atom [itex]r[/itex] , thus uncertainty in the electron velocity is equal to [itex]\Delta v \propto \frac{\hbar}{m r}[/itex]. |
| Mar11-12, 12:07 PM | #3 |
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| Mar11-12, 12:25 PM | #4 |
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stationary electron broglie wavelength |
| Mar11-12, 12:32 PM | #5 |
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| Mar11-12, 12:42 PM | #6 |
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| Mar11-12, 12:47 PM | #7 |
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| Mar11-12, 12:56 PM | #8 |
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| Mar11-12, 03:17 PM | #9 |
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hi roboticmehdi! hi sergiokapone!
![]() if we know the velocity is exactly v, then its position is again infinitely uncertain ![]() the wavelength is simply the distance it travels during a "phase rotation" of 2π … |
| Mar11-12, 05:09 PM | #10 |
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| Mar11-12, 05:12 PM | #11 |
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| broglie, electron, wave behaviour, wavelength |
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