Shape Functions FEM Homework: Derive Displacement Functions 2-10 to 2-13

In summary, the conversation is about deriving displacement functions using third cubic polynomial and elementary beam theory. The displacement functions are derived from 2-10 to 2-13. The individual is seeking clarification on how the displacement functions are derived and why certain values, such as y(0) and y(1), have specific values. The conversation also includes images of the displacement functions.
  • #1
dirk_mec1
761
13
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  • #2
Hmmm, the title should read displacement functions. The thing is I know that [itex] \xi [/itex] should run between 0 and 1 (because [itex] \xi = x/L) [/itex]. But why is the displacement: [tex]y(0) =
\theta_1 \cdot L [/tex] shouldn't there be a correction for the second angle? Moreover why is the displacement at the end zero e.g. why is y(1) =0?

By the way the picture ends like this:

http://img252.imageshack.us/img252/4352/31333995.png

ands starts like this:

http://img341.imageshack.us/img341/4606/99014438.png
 
Last edited by a moderator:

What is the purpose of deriving displacement functions in FEM homework?

The purpose of deriving displacement functions in FEM (Finite Element Method) homework is to determine the mathematical relationship between the unknown nodal displacements and the known nodal coordinates. This is essential for solving the system of equations in FEM and obtaining the solution for the problem at hand.

What are shape functions in FEM?

Shape functions in FEM are mathematical functions that are used to interpolate the values of the physical quantities (such as displacement, stress, strain) within an element. They are typically polynomials that are defined over an element and are used to approximate the actual solution of the problem.

How do you derive displacement functions in FEM?

Displacement functions in FEM are derived by applying the principle of minimum potential energy to the FEM model. This involves setting up the governing equations for the problem, applying the boundary conditions, and then solving for the unknown nodal displacements using the shape functions and the finite element method.

What are some common displacement functions used in FEM?

Some common displacement functions used in FEM are linear, quadratic, and cubic shape functions. These functions are typically used in 1D, 2D, and 3D problems respectively. In addition, there are also higher-order shape functions that can be used for more accurate solutions.

Why is it important to understand how to derive displacement functions in FEM?

It is important to understand how to derive displacement functions in FEM because it is a fundamental concept in the FEM method. By understanding how to derive these functions, one can gain a better understanding of the underlying principles of FEM and how it can be applied to solve complex engineering problems.

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