Shpae functions FEM

by dirk_mec1
Tags: functions, shpae
 P: 677 Hmmm, the title should read displacement functions. The thing is I know that $\xi$ should run between 0 and 1 (because $\xi = x/L)$. But why is the displacement: $$y(0) = \theta_1 \cdot L$$ shouldn't there be a correction for the second angle? Moreover why is the displacement at the end zero e.g. why is y(1) =0? By the way the picture ends like this: ands starts like this: