## Derivative of kinectic energy , dK/dv

i'm in my freshman year and i'm starting to learn Derivatives in Calculus, and I was wondering, once Ek (kinectic energy) = 1/2mv², then, the derivative of Ek in term of velocity would be mv, which is equal to the linear momentum..... I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way? I was just playing around deriving physics formulas haha
 PhysOrg.com physics news on PhysOrg.com >> A quantum simulator for magnetic materials>> Atomic-scale investigations solve key puzzle of LED efficiency>> Error sought & found: State-of-the-art measurement technique optimised

Blog Entries: 27
Recognitions:
Gold Member
Homework Help
Science Advisor
hi c77793!
 Quote by c77793 I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way?
it's because of Newtonian Relativity
the (Newtonian) laws of physics are the same in any inertial frame
suppose you have bodies with ∑miui2 = ∑mivi2 in one frame

now choose another frame with relative velocity w in the k-direction …
∑mi(ui - wk).(ui - wk) = ∑mi(vi - wk).(vi - wk)
cancelling (and dividing by 2) gives us …
w∑miui.k = w∑mivi.k
since w is arbitrary, we can divide by w, and get conservation of momentum in in the k direction

however, instead of cancelling, we could have differentiated wrt w (in other words, exploiting the translational symmetry of Newtonian space), giving …
w∑mi(ui - wk).k = w∑mi(vi - wk).k
(and then cancelled, giving the same result)

(btw, this also works with Einsteinian energy and momentum, in Minkowski space)

 Quote by c77793 i'm in my freshman year and i'm starting to learn Derivatives in Calculus, and I was wondering, once Ek (kinectic energy) = 1/2mv², then, the derivative of Ek in term of velocity would be mv, which is equal to the linear momentum..... I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way? I was just playing around deriving physics formulas haha
Well I was also wondering about that and I can't still find the physical relationship between the two, however both are related to force (since force is the derivative of momentum and work is (force)(distance)).
The complete derivation you can find in this thread http://www.physicsforums.com/showthread.php?t=68682
 Thread Tools

 Similar Threads for: Derivative of kinectic energy , dK/dv Thread Forum Replies Introductory Physics Homework 5 Introductory Physics Homework 3 Introductory Physics Homework 2 Introductory Physics Homework 2 Introductory Physics Homework 2