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Angular momentum and eccentricity |
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| Jul11-12, 06:02 AM | #1 |
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Angular momentum and eccentricity
I'm trying to find the relationship between angular momentum and orbital eccentricity but so far I haven't really found anything. I did find an indirect relationship, though, which looked like it should come out to,[tex]L=\sqrt{\frac{a(1-e^{2})}{m_{1}+m_{2}}},[/tex] but I may be completely wrong. Anyone know the correct answer?
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| Jul11-12, 11:35 AM | #2 |
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Mentor
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Even if you remove as many variables as possible, orbits always have two degrees of freedom, they can be written as semi-major axis and eccentricity. The angular momentum will depend on both, together with the masses and the gravitational constant.
I found this formula at wikipedia: ![]() The energy is [itex]E = \frac{-G(M+m)}{2a}[/itex] Therefore, [itex]e^2 = 1-\frac{c}{a} L^2[/itex] with [itex]c=\frac{M+m}{GM^2m^3}[/itex] and [itex]L=\sqrt{\frac{1-e^2}{ca}}[/itex] where c just depends on the masses. |
| Jul16-12, 04:24 PM | #3 |
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Thanks very much.
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