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Assumptions of Landau theory |
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| Aug20-12, 12:02 PM | #1 |
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Assumptions of Landau theory
Assume that we can expand the Helmholtz potential about [tex]T=T_c[/tex], [tex]M=0[/tex] in a standard Taylor series form of functions of the variables,
[tex]A(T,M)=\sum^{\infty}_{j=0}L_j(T)M^j=L_0(T)+L_2(T)M^2+L_4(T)M^4+...[/tex] Why [tex]A(T,M)[/tex] must be even function of [tex]M[/tex]? Coefficients can be expanded about [tex]T=T_c[/tex] [tex]L_j(T)=\sum^{\infty}_{k=0}l_{jk}(T-T_c)^k=l_{j0}+l_{j1}(T-T_c)+...[/tex] How I could no that coefficients are analytic functions od [tex]T[/tex]. |
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| Aug20-12, 03:49 PM | #2 |
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Consider a system of spins, where M is the coarse-grained magnetization of a certain “block.” In that block, if I flip every spin then there is no change in the energy in the system. Flipping of all the spins would result in M → -M. That’s why A(T,M) is even in M. I didn't quite understand your second question about analyticity
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| Aug20-12, 05:33 PM | #3 |
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Recognitions:
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You'll find out eventually that it's actually a bad assumption. |
| Aug22-12, 09:19 AM | #4 |
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Assumptions of Landau theory
I think that this is very hard problem, and not precise theory.
Helmholtz potential is convex function of magnetisation. [tex]A(T,M)=\sum^{\infty}_{j=0}L_j(T)M^j[/tex] that must put some demands on coefficients in series, and if I say [tex]L_j(T)=l_{j0}+l_{j1}(T-T_c)+...[/tex] I have a problem with different behavior below [tex]T_c[/tex] and for [tex]T>T_c[/tex]. So is there coefficients [tex]l_j[/tex] positive or negative? |
| Aug22-12, 01:59 PM | #5 |
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