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Blackbody Heat Shields/Metal Sheets

 
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Sep21-12, 03:28 AM   #1
 

Blackbody Heat Shields/Metal Sheets


A “blackbody heat shield” is used to reduce radiant heat loss in situations where standard low conductivity insulation (i.e. normal insulation) cannot be used. The shield is constructed using a set of parallel metal sheets, each with emissivity 1.0.

Explain how/why this “heat shield” works and determine how many sheets of metal are
required to reduce the heat loss to less than 20% of the unshielded value. (Hint: think
about the radiation absorbed by each sheet and how this energy will be re-radiated.)

Diagram:


I really need help with this xD I don't even know where to begin.
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Sep21-12, 07:36 AM   #2
mfb
 
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Here are some ideas:
- assume that the whole problem is 1-dimensional
- begin with 1 heat shield: Where does it receive/emit radiation?
- assuming that the environment has a temperature of ~0, calculate the temperature of that heat shield in equilibrium
Sep21-12, 09:33 AM   #3
 
ummmm I still don't get it xD

do I use the equation:

Q = mC deltaT?
Sep21-12, 09:46 AM   #4
mfb
 
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Blackbody Heat Shields/Metal Sheets


No, that looks like regular conduction.
##P_{emitted}=\sigma A T^4## (Stefan-Boltzmann)
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heat shield, radiant, thermal
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