
#1
Nov1212, 08:18 AM

P: 71

I have an electromagnetic field with a Poynting vector that has the following form in spherical coordinates:
$$\bar{P}(R,\phi,\theta)=\frac{f(\phi,\theta)}{R^2}\bar{e}_{r}$$ The exact nature of [itex]f(\phi,\theta)[/itex] is not known. Suppose I measure the flux of this vector field by a flat area detector. The pixel values of an image acquired by such a detector are given by $$I_{\text{pixel}}(x,y)=\iint_{\text{pixel}} \bar{P} \cdot \bar{\text{d}S}=\iint_{\text{pixel}} \left\\bar{P}(x,y)\right\\cos(\alpha(x,y))\ \text{d}x\text{d}y$$ where [itex]\alpha[/itex] the (known) angle between detector surface and Poynting vector and [itex]XY[/itex] the detector plane in the detector reference frame [itex]XYZ[/itex] for which we know the relation to the [itex]\bar{P}[/itex] coordinate system. From this I want to know the pixel values as would have been measured when the detector had another orientation and position with respect to the origin of [itex]\bar{P}[/itex] $$\begin{bmatrix}x'\\y'\\z'\\1 \end{bmatrix} =L\cdot\begin{bmatrix}x\\y\\z\\1\end{bmatrix}$$ where [itex]L[/itex] a know composition of rotations and translations or even for a spherical detector. How can I do this? The Jacobian can be used when the transformation only involved the detector plane [itex]XY[/itex]. However this is not the case and I can also not use the divergence theorem, since we don't have a closed surface. Any ideas on how to approach this? 



#2
Nov1512, 09:44 PM

P: 4,570

Hey Wox.
Have you encountered unfixed coordinate system mathematics and calculus through tensors? 



#3
Nov1612, 03:18 AM

P: 71

I'm not sure what you mean by "unfixed coordinate system mathematics". You mean vector spaces without choosing a basis?
As for tensors, this is what I know: a tensor product of two vector spaces [itex]V[/itex] and [itex]W[/itex] both over field [itex]K[/itex] is a pair [itex](T,\otimes)[/itex] where [itex]T[/itex] a vector space over [itex]K[/itex] and [itex]\otimes\colon V\times W\rightarrow T[/itex] a bilinear map with the property that for any bilinear map [itex]B_{L}\colon V\times W\rightarrow X[/itex] with [itex]X[/itex] a vector space over [itex]K[/itex], there exists a unique linear map [itex]F_{\otimes}\colon T\rightarrow X[/itex] so that [itex]B_{L}=F_{\otimes}\circ\otimes[/itex]. Furthermore if [itex](T,\otimes)[/itex] and [itex](T',\otimes')[/itex] are two tensor products of [itex]V[/itex] and [itex]W[/itex] then there exists a unique isomorphism [itex]F\colon T\rightarrow T'[/itex] such that [itex]\otimes'=F\circ\otimes[/itex]. Although I understand what all this says (I know vector spaces, bilinear maps, linear maps, bijective linear maps = vector space isomorphisms), I don't really grasp the idea or the practical implications. But any suggestions you have are welcome, if I don't understand I'll try to learn it. 



#4
Nov1612, 05:31 AM

P: 4,570

Flux in different coordinate systems
The application physically is widespread:
http://en.wikipedia.org/wiki/Applica...ory_in_physics It has to do with what you are saying, but basically you have identities that deal with things like del, grad, differentiation and integration in arbitrary coordinate systems by relating them back to Euclidean since we have a developed theory in R^n. The isomorphism is the best attribute that captures the description but instead of just thinking about vector spaces, add the results of calculus to that and you have a good idea of how its used. 


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