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How to know a transistor is carrying out its function ? |
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| Nov21-12, 03:37 AM | #1 |
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How to know a transistor is carrying out its function ?
For a npn transistor, Vb= +0.7V ,Vc=+1.0V , Ve=0
Then my teacher says it is not operating, why is that so? Thank you. |
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| Nov21-12, 06:37 AM | #2 |
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I see no reason to believe the transistor as specified is not operating.
Let us suppose a 5 volt supply and a 3k9 collector resistor, then with the figures stated the current through the collector resistor Rc is (5-1)/3.9 milliamps which is a litle over 1 milliamp. This is also the collector current and perfectly acceptable. I wonder if there is not a typo with the figures, for example is there a missing negative sign or has someone mixed up Vc and Ve? |
| Nov21-12, 09:25 AM | #3 |
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No typo, my teacher said Vb is +0.7V Ve=0 Vc=+1.0V My teacher said although this is in active mode, the transistor is now off( not carrying out its function as in active mode) as Vb-Vc is less than 0.5V I can't understand why is that so? |
| Nov21-12, 09:54 AM | #4 |
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How to know a transistor is carrying out its function ?
Attached is the simplest arrangement to setup your conditions.
Say the collector resistor is 3k9 (as before) and the beta of the transistor is 100 then the base will require 1/100 milliamps current (10 microamps) as in the diagram there is 4.3 volts across the base bias resistor so Rb = 4.3 / (1/100) k ohms = 430 k say 390k as nearest preferred value. Your teacher is somehow mistaken. There is nothing whatsoever wrong with the collector being only 0.3 volts above the base. In fact in some circuits in saturation the collector could be taken below the base (ie negative with respect to the base). This condition is called saturation and is what is required in a switching transistor. The collector - emitter voltage of the type of transistor I talk about here will be about 0.2 volts ie the collector will be at +0.2volts. The base will still be at +0.7 volts. |
| Nov21-12, 11:13 AM | #5 |
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So do you mean that 'Vb-Vc is less than 0.5V' does not mean anything in an active mode of transistor? |
| Nov21-12, 12:07 PM | #6 |
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This is bound to happen in proper normal operation as an amplifier. One of the manufacturers published parameters is Maximum Collector-base voltage Vcb which is usually several tens of volts. You have posted this in the electrical engineering section. Physicists are interested in how a transistor works from the point of view of junctions, cariers, holes elctrons etc. Electrical engineers are not really interested in this but want a model that allows them to predict quantities of interest to create useful circuit configurations. Which are you interested in? |
| Nov21-12, 05:22 PM | #7 |
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In npn, Now the base-collector is highly reversed biased. So now the transistor is still carrying out active mode? Thank you. |
| Nov21-12, 08:11 PM | #8 |
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I think we need to know the configuration before we go farther. Schematic please?
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| Nov21-12, 10:08 PM | #9 |
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Given Vbe=0.7V
Vb=0.7V Ve=0 Vc=5.0V Ib=0.45μA Ic=100Ib |
| Nov22-12, 12:03 AM | #10 |
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Recognitions:
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If that's what you are saying, then the transistor is certainly in the active region. That's how the active region is defined: collector current is controlled by and directly proportional to base current. Yes, even if VC = 0.5V. (N.B. Even when a transistor is operating in saturation, we still say it is "working" and "carrying out its function", etc. That's the function of a transistor switch.) |
| Nov22-12, 01:16 AM | #11 |
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So do you mean that the transistor is operating in active mode for the question post #9 ?
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| Nov22-12, 04:28 AM | #12 |
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Recognitions:
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(Did you intend to type 5 V there, or did you mean 0.5V?) |
| Nov22-12, 05:19 AM | #13 |
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5V . because of I want to ask what will happen when it is highly reverse biased .
Thank for replying. |
| Nov22-12, 05:31 AM | #14 |
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I do not believe that the circuit arrangement you showed in post#9 will lead to the voltage values etc you listed.
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| Nov24-12, 02:45 AM | #15 |
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| Nov24-12, 03:11 AM | #16 |
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Can you see the difference between your arrangement and my post#4?
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| Nov24-12, 03:15 AM | #17 |
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