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Oppenheimer-Snyder model of star collapse |
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| Nov19-12, 12:05 AM | #86 |
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Oppenheimer-Snyder model of star collapse |
| Nov19-12, 10:59 AM | #87 |
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But probably we will discuss that in your new thread, http://www.physicsforums.com/showthread.php?t=652839 |
| Nov19-12, 12:51 PM | #88 |
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But again, as seem so common, I am not sure I understand what your are getting at. Probability of this seems 99% bidirectional between us. |
| Nov21-12, 07:09 AM | #89 |
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| Nov23-12, 03:09 AM | #90 |
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Voyager 35 is sent to a newly discovered black hole only about 20 light years away and which for simplicity we assume to be eternal static, and in rest wrt the solar system. The Voyager is indestructible and always in operation. A time code is emitted from Earth that can be received by Voyager. Voyager emits its proper time code s1 that is sent back to Earth together with the then received time stamp t1 from Earth (we'll ignore the technical difficulties). An observer on Earth with the name Kraus calculates the expected (s1,t1) signal from Voyager as function of expected UTC, for the approximation or assumption that the black hole is completely formed. He stresses that he could choose other coordinates, but that the "SC" of Oppenheimer-Snyder-1939 are fine and valid for making predictions about what can be observed on Earth, making small corrections for Earth's gravitational field and orbit. He finds something like the following (I pull this out of my hat, just for the gist of it): UTC , (s1 , t1) -------------- 100 , 40.3, 200 1E3 , 41.2, 1.5E3 1E4 , 41.5, 1E5 1E5 , 41.7, 1E7 1E6 , 41.9, 1E10 1E100 42.0, 1E1000 My question: Please give an illustration of time codes t1 from Earth that reach Voyager at τ=43, as it has gone through the horizon. |
| Nov23-12, 06:00 AM | #91 |
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I have trouble imagining the Krauss quantum phenomena in the case of PAllen's trillion star contractring cluster. Surely in this case an event horizon would form long before any quantum radiation is emittted. The stars are still well separated when the black hole forms!
Mike |
| Nov23-12, 09:18 AM | #92 |
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- Earth emits a signal time stamped with the time t1 of emission according to Earth clocks. - Voyager receives the signal, and emits a return signal time stamped with the time s1 of emission according to Voyager's clock, plus the Earth emission timestamp t1 of the Earth signal just received. - Earth wants to predict the (s1, t1) pairs that it will receive in Voyager's return signal, as a function of the time UTC that it receives the return signal. A correct set of numbers would look something like this (I haven't calculated these numbers exactly, I've just tried to give a fair approximation of the qualitative behavior): t1, s1, UTC ------------- 40, 40.3, 200 40.5, 41.2, 1.5E3 40.7, , 41.5, 1E5 40.8. , 41.7, 1E7 40.9, 41.9, 1E10 40.99, 41.99, 1E1000 (...) 41, 42, (Earth never receives any return signal from here on) 41.3, 43 41.6, 44 41.8, 45 42, 46 42.2, 47 42.3, 48 42.300001, (Voyager never receives any Earth signal from here on, it is destroyed in the singularity at tau = 48) |
| Nov23-12, 10:55 AM | #93 |
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To help make sense of the numbers in my last post, attached is a Kruskal-type plot of the scenario. (I made it using fooplot.com, which seems like a neat if simple online tool for generating plots.)
Quick description of the plot: - The horizontal and vertical axes are the Kruskal U and V coordinate axes. - The black hyperbola at the top is the singularity at r = 0. - The crossing 45 degree gray lines are the horizon (up and to the right) and the antihorizon (up and to the left). In a more realistic model where the black hole was formed by the collapse of a massive object, the antihorizon would not be there; instead, there would be the surface of the collapsing object on the left as in the diagram DrGreg posted some time ago. - The blue hyperbola on the right is the Earth's worldline. - The dark red curve that leaves Earth at U = 0 (i.e., just as Earth crosses the horizontal axis--this is also t = 0 on Earth's clock) is Voyager's worldline; Voyager leaves Earth and falls into the hole. - The three progressively darker green lines, running from Earth up and to the left towards Voyager, are three of the light signals emitted from Earth, at Earth times (according to the numbers in my previous post) 40 (more or less--the qualitative behavior is the key here, not the exact numbers), 41, and 42.3. Note what happens to them: Signal #1 reaches Voyager before it crosses the horizon; Voyager then emits a return signal (the 45 degree line going up and to the right from where #1 reaches Voyager), which reaches Earth further up its worldline, at t = 200 (more or less). You can see that signals emitted in between #1 and #2 from Earth will be received by Voyager closer and closer to the horizon, so Voyager's return signals will reach Earth further and further up its worldline, i.e., at later and later times, increasing without bound. Signal #2 reaches Voyager just as it crosses the horizon. Voyager's return signal therefore stays at the horizon; it never reaches Earth. Signals emitted from earth between #2 and #3 will reach Voyager between the horizon and the singularity, so its return signals will stay below the horizon and also never reach Earth (eventually each of these return signals will hit the singularity). Signal #3 reaches Voyager just as it hits the singularity. Any signal emitted from Earth after #3 will never reach Voyager, because it is destroyed in the singularity; these signals will hit the singularity instead. |
| Nov23-12, 03:58 PM | #94 |
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Correct? The t1 numbers in the beginning are surprising to me; you seem not to account for the ca. 20 light years in "distant" units in your estimated prediction. And/or you assume that the different time dilation factors largely compensate each other. [Addendum]: in fact I assumed the Voyager to circle for some years in orbit, thus ticking slower; and I suddenly realise that I added instead of subtracted the 20 years - I was in a hurry! What could be relevant for this discussion (although likely also not) is your (t1,s1) = (40.99, 41.99). I don't know how you get that 1 year difference, is that just a coincidence? Now I'll study the rest; the issue is really (t1,s1)= (41.3, 43). I do think that earth must get a signal back (41.3, 41.9999999999) according to O-S-1939. |
| Nov23-12, 04:10 PM | #95 |
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| Nov23-12, 05:26 PM | #96 |
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Oops I was still editing my post, trying to reconstruct what went wrong in not -so-important details.
"we see that for a fixed value of R as t tends toward infinity, τ tends to a finite limit". That is also what online simulators find (in fact I now found a nice one in Java. )The real issue is the last point in my addendum, which was also the intended point of the illustration. To be discussed tomorrow!
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| Nov23-12, 05:42 PM | #97 |
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I'll comment on your addendum in a separate post. |
| Nov23-12, 05:56 PM | #98 |
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![]() O-S do say, however, that when the surface of the infalling matter reaches the horizon radius (what they call r_0)--this corresponds to Voyager's clock reaching tau = 42--outgoing light can no longer escape (hence the infinity as the limit of the UTC times above as t1, s1 -> 41, 42). This seems like a pretty clear indication that *if* O-S had continued their analysis and discovered that points on Voyager's worldline with tau > 42 could exist, they would find (as modern analyses have found) that those points would not be able to send light signals back to Earth; since if outgoing light can't escape from the event where tau = 42, at r = r_0, any event with tau > 42 must have r < r_0 (since r > r_0 would require Voyager to move faster than light from the tau = 42 event, and even r = r_0 would require Voyager to move at the speed of light from the tau = 42 event), and would also not be able to send signals back to Earth (since those signals would also have to move faster than light). If you think otherwise, please give specific references from the paper. I've read it through now and what I've said about the model in that paper and its limitations is based on what I've read. A final note about the 20 light-year distance: that would just add an irrelevant constant to every s1 value and every UTC value. Instead of triples like (40, 40.3, 200), you would get, for example, (40, 40.3 + 20 years, 200 + 20 years); and instead of triples like (40.99, 41.99, 1E1000), you would get, for example, (40.99, 41.99 + 20 years, 1E1000 + 20 years), which works out to a very good approximation to (40.99, 41.99 + 20 years, 1E1000). So the 20 years quickly becomes negligible compared to the huge increase in UTC values compared to the other two. Rather than add 20 years to the s1 and UTC values as above, I chose to ignore the 20 light year distance and assume that Earth was much closer to the hole. But I can put back in the 20 light year distance when I do the detailed calculations if you think it's really important (I don't think it is, since it doesn't change the qualitative behavior). |
| Nov24-12, 05:42 AM | #99 |
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http://www.compadre.org/osp/items/detail.cfm?ID=7232 Put r=7.414 and τ gets to nearly 42 as in my original illustration. ![]() ![]() However there was an essential point that I overlooked: in the model of a fully formed black hole Voyager remains in free-fall towards the centre, so that it may be expected to outrun certain radio waves (thanks for pointing that out Atyy!). Consequently I will almost certainly agree with your calculation about by us observable events - thank you too.
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| Nov24-12, 12:28 PM | #100 |
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| Nov25-12, 04:06 AM | #101 |
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. Regretfully I don't know Java. Now that I finally got an understanding of the "inside region" arguments, I can zoom in on the real issues - which did not go away. But before continuing I want to make sure of one thing: Like me, you seem to relate the motion of matter with respect to such a reference system in which space does not have a velocity vector; and my impression is that the O-S model that they presented is consistent with that. |
| Nov25-12, 12:29 PM | #102 |
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However, I wasn't making a statement about coordinates; I was making a statement about physics. The original Schwarzschild model was of a spacetime that is entirely static--nothing changes with time. The O-S model is of a spacetime that is only partially static; the region containing the collapsing matter is not static, it changes with time, and so does the radius of its boundary with the vacuum region. So if I am at a certain radius that is greater than the radius r_0 (what we would now call the horizon radius), the metric in my vicinity only becomes static once the collapsing matter falls past me to a smaller radius. That's true regardless of what coordinates I use. |
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