
#1
Dec512, 12:57 AM

P: 31

1. The problem statement, all variables and given/known data
Determine the average value of the following function over the interval [0,6] f(t) = (t^{2}1)e^{0.5t} 2. Relevant equations 1/(ba) ∫ f(x) = {f(x)} 3. The attempt at a solution Substitution? let u = (t^{2}1) du/dt = 2t du/2t = dt 1/(6) ∫ u e^{0.5t} (du/2t) And here, I reach a roadblock. 



#2
Dec512, 01:00 AM

P: 2,472

so to get the average of the function you integrate the function and then divide by the interval length.




#3
Dec512, 01:01 AM

Emeritus
Sci Advisor
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Thanks
PF Gold
P: 11,521

Try a different technique.




#4
Dec512, 09:49 AM

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HW Helper
PF Gold
P: 7,391

Average Value of a Function 


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