Register to reply

An element of a finite group

by llauren84
Tags: element, finite
Share this thread:
llauren84
#1
Dec15-12, 12:27 AM
P: 44
I need help with this theorum, please.

How is this (the attachment) true? It's for my cryptology class.

The rest of the day's notes are here: http://crypto.linuxism.com/thursday_december_13_2012
Attached Thumbnails
math.png  
Phys.Org News Partner Science news on Phys.org
Mysterious source of ozone-depleting chemical baffles NASA
Water leads to chemical that gunks up biofuels production
How lizards regenerate their tails: Researchers discover genetic 'recipe'
Number Nine
#2
Dec15-12, 02:19 AM
P: 772
You might try applying Lagrange's theorem; that should set you in the right direction.
Stephen Tashi
#3
Dec15-12, 02:30 AM
Sci Advisor
P: 3,283
If [itex] G [/itex] is a finite group with order [itex] |G| [/itex] then for each element [itex] a \in G [/itex] , [itex] a^{|G]} = I [/itex], the identity.
Are you asking how to write a proof of the theorem or for some intuitive indication why it is true?

llauren84
#4
Dec15-12, 03:58 AM
P: 44
An element of a finite group

LaGrange's theory helped thanks. Also, the rewritten form of the statement helped, so thanks both of you.


Register to reply

Related Discussions
Proving one element in the symmetric group (s>=3) commutes with all element Linear & Abstract Algebra 2
Finite element method versus intergrated finite difference for complex geometries? Differential Equations 6
In a finite group G, the inverse of each element is a power of itself. Calculus & Beyond Homework 2
A question of element order of finite group Linear & Abstract Algebra 0
Beam element vs. Finite element? Mechanical Engineering 3