
#19
Dec2212, 08:00 PM

P: 217

y direction (g*sin(theta)) or (g*Cos(theta)) for AD or CD.. well CD would the x component right? 



#20
Dec2212, 08:21 PM

P: 17

For AD, I would use cos(theta) (the component in the X direction) as it will give you the velocity you need for segment CDo Since there is no acceleration during CD,there are no sin or cos to worry about
Be sure to convince yourself of this as understanding these concepts will make the rest of your semester considerably easier 



#21
Dec2312, 03:30 PM

P: 217





#22
Dec2312, 11:41 PM

P: 17

If that's the case then it would be because I misunderstood your sketch as the letters weren't entirely clear to me. Regardless, it sounds like you have the right idea. Good luck.




#23
Dec2412, 02:13 PM

P: 217





#24
Dec2412, 02:57 PM

PF Gold
P: 1,054

This speed is equal to the final speed at C, after the car has traversed path AC. The speed along AC is not constant. Initially, at A, it is zero. Do you know how to find the speed at C? 



#25
Dec2412, 03:09 PM

P: 217

So i would find the V2 = speed from A to C CD and then i would use this V2^2  v1^2 = 2ad V1^1 = the speed found for AC V2^2 = need to find right? 



#26
Dec2412, 03:18 PM

PF Gold
P: 1,054

I added comments in blue




#27
Dec2412, 03:36 PM

PF Gold
P: 1,054

Please see my edits.




#28
Dec2412, 03:41 PM

P: 217

v2^2 = 2gd V2 = 44.27188724 m/s Velocity from C to D or D to C V2^2 = 2gd + v1^2 v2^2 = 2(9.8)(100) + (44.27188724 m/s)^2 v2 = 62.60990337 m/s 



#29
Dec2412, 03:54 PM

PF Gold
P: 1,054

Comments in blue




#30
Dec2412, 04:16 PM

P: 217

I know u guys said to keep the velocity constant which is this 44.27188724 m/s [right]... 



#31
Dec2412, 04:23 PM

PF Gold
P: 1,054

Can you please reformulate your last post into one or more questions? 



#32
Dec2412, 04:41 PM

P: 217





#33
Dec2412, 09:14 PM

PF Gold
P: 1,054

My comments in blue




#34
Dec2512, 09:24 AM

P: 217





#35
Dec2512, 09:34 AM

P: 17

If you are able to find the final velocity at the end of the ramp (I'll call V), then the time from C to D can be found with:
V = CD * t Where CD is the distance between CD. When on a friction less, horizontal plain; the force due to gravity is equal and opposite to the normal force and no acceleration takes place. Since the plain lacks friction, there is no deceleration. Therefore, velocity stays constant during CD 



#36
Dec2512, 09:38 AM

Mentor
P: 10,774

Velocity is distance per time. 


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