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Determinant systems

 
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Dec26-12, 09:44 AM   #1
 

Determinant systems


am not a math guru :P,am a newbie even if this should be solved by a newbie as well, Id like u guys to help me out to solve this one :

3x-y+2z=4

Im really needing this, thank you all.
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Dec26-12, 10:04 AM   #2
 
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One equation, three unknowns.

You can solve this equation as long as you pick values for any two of the unknowns.
Dec26-12, 10:16 AM   #3
 
Quote by SteamKing View Post
One equation, three unknowns.

You can solve this equation as long as you pick values for any two of the unknowns.
can u give me a hand now ? :)
3x+y+2z=4
2x+3y-z=4
2x-y-z=0
Dec26-12, 10:45 AM   #4
 
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Determinant systems


You could either convert it into a matrix equation and solve it.

Or you can use one equation to modify the other two, and then solve those two simultaneously. For example if you take the last equation and substitute it into the first 2, then solve the now modified first two you will get two of the solutions.
Dec26-12, 10:54 AM   #5
 
Thank you guys. But when its up to math in english im not good,actually im not understanding this that much, i need someone to solve it in mathematical view..
Dec26-12, 11:36 AM   #6
 
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Quote by poon View Post
Thank you guys. But when its up to math in english im not good,actually im not understanding this that much, i need someone to solve it in mathematical view..
Do you know how to form a matrix equation from a system of equations?

3x+y+2z=4 (1)
2x+3y-z=4 (2)
2x-y-z=0 (3)

If you take equation 2 and subtract that from equation 3, what equation are you left with?

Similarly, if you take equation 1 and add that to 2*equation 3, what equation are you left with?
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