|Jan31-13, 11:39 AM||#1|
Why can't optical phonons travel far?
I can't figure this out/find the answer. Why are acoustic phonons very low loss (i.e. earthquake P and S waves), but optical phonons die out rapidly?
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|Jan31-13, 08:55 PM||#2|
What mechanisms have you considered?
In what sense are phonons "low loss"? What does that mean exactly?
|Feb2-13, 06:59 AM||#3|
The energy loss is low is because of the low frequency/longer wavelength phonon - which does not coincide with the size of the molecules/atoms. The higher frequencies/shorter wavelength phonon is likely to coincide with the size of the molecules/atoms, and thus losing its energy through resonating the energy through all the molecules/atoms. This is the cause of energy attenuation.
Another factor is energy dissipation: By having the size of molecules/atoms coinciding close to that of the phonon, the phonon streams is more likely to be reflected/refracted and thus dissipated.
Both of these factors can help to explain why longer wavelength can travel far, low signal loss.
Another possible explanation is the phonon density: higher frequencies phonon matches with that of smaller atoms/molecular structures, which occurred at a higher density/number, and thus is able to spread the energy faster. Lower frequencies/longer wavelength need larger molecular structures (or multiple atom forming a macro-structures), which occur at a much lower densities, and thus is less able to spread the energy faster.
Another possible dissipative phenomena is electron-phonon coupling, which is more likely to happen for higher frequencies phonons.
These are my layman's perspective of what's happening, but from a specialist point of view (beyond me), u can refer to:
http://www.iop.vast.ac.vn/theor/conf...roc/35/153.pdf (on resonance)
http://ocw.mit.edu/courses/chemistry...23_562ln08.pdf (which correlate the wavelength of the phonon with the size of the molecule/atom)
http://www-ee.eng.buffalo.edu/facult...Papers/115.pdf (on electron-phonon coupling)
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