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#1
Feb913, 10:38 AM

P: 123

I realize that the people here must be sick of answering stupid questions about the double slit experiment, and different ways of setting it up, but if I may, I have a question about what you would expect to see if the double slit experiment were set up in a slightly different manner, and why.
First, I am assuming that in the classic double slit experiment we need only put a detector at one slit in order to destroy the interference pattern. But this leaves me with a question. Is it the fact that we then know which slit the particle went through that destroys the interference pattern, or is it the fact that we interacted with the probability wave that destroyed the interference pattern? In other words, could we destroy the probability wave without knowing which slit the particle went through. So my question is, what if, instead of setting up the double slit experiment in the way that I usually see it portrayed, with something that looks like a laser pointed at a wall with two slits in it, but instead we set it up with a light positioned in the center of a box with a pair of slits on each of the six opposing walls, and a screen positioned behind each pair of slits. I assume that absent any detectors we would expect to see an interference pattern on all six of the screens. But what if we then put a detector on just one of the twelve slits? Would that one detector be sufficient to destroy the interference pattern on all six of the screens? Or would it only destroy the interference pattern on the screen positioned behind the wall with the detector? What would you expect to see with such a setup, and why? Thanks to everyone for considering my question. 


#2
Feb913, 11:30 AM

Sci Advisor
Thanks
P: 2,337

I'm never sick about answering (or at least trying to answer) such questions.
I always find these ideas on whichway information vs. the observation of an interference pattern quite vague. One should clearly specify the experiment and analyse it. Then most of the quibbles with quantum theory vanish usually in a natural way. One must also state clearly which interpretation of quantumt theory one follows. I'm using the minimal statistical interpretation. Now let's consider the usual doubleslit experiment. Let's use single photons of a welldefined linear polarization and frequency. Hitting the double slit without any device to determine through which of the slits the photon has gone with very many of such prepared photons, you'll find the doubleslit interference pattern on the detection screen. Now the question is, how you can (at least in principle) gain "whichway information" for each single photon with certainty. This is only possible by somehow "tagging" each photon with the information through which slit it might have come. This can be easily achieved by, e.g., putting quarterwave plates into the slits. Such a quarterwave plate transforms the linearpolarization state into an elliptically polarized state. If we choose the orientation of the quarterwave plates to be [itex]45^{\circ}[/itex] in the one slit and [itex]45^{\circ}[/itex] in the other, with the angle measured relative to the polarization direction of the incoming photon, then any photon, coming through slit 1 becomes leftcircular (helicity 1) and any photon coming through slit 2 becomes rightsingular (helicity +1) polarized. These polarization states are completely disinguishable, because the corresponding state kets are orthogonal to each other. Now, orthogonal states can never interfere, and thus you won't see any twoslit interference pattern anymore, because the two ways a photon can run to hit the screen are now completely distinguishable, because this information is inherent in any photon behind the double slit. Thus the possibibilities cannot interfere anymore, and thus you don't see an interference pattern. There are very clever setups of this kind, using entangles photon pairs, where you can choose, whether you want to see the interference pattern or not by looking on subensembles of the complete ensemble after the whole experiment has been performed and the data on the position of each photon hitting the screen are fixed. Thus you can "erase" the whichway information for a subensemble of the whole ensemble such that the subensemble shows the interference pattern again. See this publication for details: S. P. Walborn, M. O. Terra Cunha, S. Pádua, C. H. Monken, Doubleslit quantum eraser, Phys. Rev. A 65, 033818 (2002) http://link.aps.org/abstract/PRA/v65/e033818 It's also nicely described on the following website: http://grad.physics.sunysb.edu/~amarch/ Concerning your alternative setup, I don't see how the six doubleslit experiments should be correlated. By just putting a light source into the box, for sure they are not related in any way. 


#3
Feb913, 11:44 AM

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#4
Feb913, 02:21 PM

P: 123

Another double slit question
In the classic double slit experiment, with a detector at both slits, how do the detectors introduce decoherence? Dumb question I know. 


#5
Feb913, 02:51 PM

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P: 11,601

The detectors interact with the wave function "in some way" (enough to cause decoherence, i.e. a phase shift which cannot be predicted).



#6
Feb913, 03:14 PM

P: 123




#7
Feb913, 03:38 PM

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P: 11,601

It interacts according to the laws of physics, which are wellknown for usual detectors.
It depends on the precise quantummechanical state of the detector (which we usually do not know), and the used method of course. 


#8
Sep2013, 09:53 AM

P: 55

"Now, orthogonal states can never interfere, and thus you won't see any twoslit interference pattern anymore, because the two ways a photon can run to hit the screen are now completely distinguishable, because this information is inherent in any photon behind the double slit. Thus the possibilities cannot interfere anymore, and thus you don't see an interference pattern."
This is exactly a point I wanted to ask about. If orthogonal states can never interfere anyway, then that and that alone is the reason for the lack of fringes. We don't need to say simply knowing or not knowing which slit the photon came through is reason for the state of the photon. It is the quarterwave polarizers that destroy the interference pattern. In other words, even if the photon went through both slits as a probability wave, and not just one as a particle, the interference pattern would still be destroyed. So, how does this experiment prove anything at all? 


#9
Sep2013, 10:34 AM

P: 844

So why do people say that measuring "which path" information destroys the interference? The interference is destroyed because if you measure which path information, you change the paths so that they reach different final states. One final state is "electron hits the wall at x=5 and the detector reads 'left path,'" while the other final state is "electron hits the wall at x=5 and the detector reads 'right path.'" Since these final states are different, the two paths can't interfere. This sort of thing is going to happen no matter how you detect which path the electron took, so in general "which path" measuring devices destroy the interference pattern. This also makes it clear that it's not just deliberate measurements that destroy interference. If there's a single stray photon that scatters off the electron if it takes the right path, but not the left path, then this will lead to different final states: "electron hits the screen at x=5 and photon was scattered" vs "electron hits the screen at x=5 and photon was not scattered." So this single stray photon will destroy the interference pattern. Of course, you can think of the photon as performing a crude and accidental "measurement" of which path the electron took. 


#10
Sep2013, 12:12 PM

Sci Advisor
PF Gold
P: 5,299

So we are saying that the wave function for a single photon describes something which is physically real (according to your interpretation of course), and that wave traverses both slits  not just one. 


#11
Sep2113, 12:35 AM

P: 55




#12
Sep2113, 03:38 AM

P: 3,184

In particular starting from post #21 See also links to similar discussions at the bottom of that page. 


#13
Sep2113, 05:24 AM

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P: 11,601

If you use collapse interpretations, you have to "wait" with the full collapse until the whole process is done. 


#14
Sep2213, 01:32 AM

P: 1,074




#15
Sep2213, 08:01 PM

Sci Advisor
PF Gold
P: 5,299

So the upshot is: if you accept the conventional interpretation and join the scientific consensus, and you can call it whatever you want. Even an "illusion". 


#16
Sep2213, 08:34 PM

P: 12

On what evidence,or why,does everyone assume that the photon leaves the source? Why does everyone assume that the photon is an autonomous entity before it entangles with the destination?
If people use the double slit experiment to prove for themselves that the photon is in 2 places,why then are they comfortable with having the photo a SEPERATE! entity from the source? 


#17
Sep2213, 08:43 PM

P: 12

Could the photon not be a long quivering filament of energy attached to the source,only becoming a particle when entanglement occurs?It would be this filament that passes through the slit,and not the entire photon(until it hits the screen(entanglement)?



#18
Sep2313, 07:19 AM

Mentor
P: 11,601

You can know that a photon left the source (with a proper singlephoton source), close the source, and only then let your photon go through the double slit. That does not change anything, and I don't see the relevance for the double slit experiment.



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