Laplace transform sqaured differential


by opul
Tags: laplace derivative, squared
opul
opul is offline
#1
Feb24-13, 03:06 PM
P: 2
Hi

I was wondering what the Laplace transform of a squared differential is.
With that I mean the Laplace of (y' )^2 (this being y'*y' and not the second order derivative). So for example velocity squared.
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rbj
rbj is offline
#2
Feb24-13, 06:16 PM
P: 2,265
there is a lot of similarity between the Fourier Transform and the Laplace Transform. the F.T. is really just the L.T. with the real part of [itex] s = \sigma + i \omega [/itex] set to zero. try to answer the question regarding the F.T. and see if you can generalize.
the_wolfman
the_wolfman is offline
#3
Feb25-13, 07:36 PM
P: 135
I don't know the exact form off the top of my head, but it will be an ugly convolution of the form:

integral (s^2 F(a)F(a-s) da)


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