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Laplace transform sqaured differential |
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| Feb24-13, 03:06 PM | #1 |
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Laplace transform sqaured differential
Hi
I was wondering what the Laplace transform of a squared differential is. With that I mean the Laplace of (y' )^2 (this being y'*y' and not the second order derivative). So for example velocity squared. |
| Feb24-13, 06:16 PM | #2 |
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there is a lot of similarity between the Fourier Transform and the Laplace Transform. the F.T. is really just the L.T. with the real part of [itex] s = \sigma + i \omega [/itex] set to zero. try to answer the question regarding the F.T. and see if you can generalize.
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| Feb25-13, 07:36 PM | #3 |
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I don't know the exact form off the top of my head, but it will be an ugly convolution of the form:
integral (s^2 F(a)F(a-s) da) |
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