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Implications of the statement "Acceleration is not relative" |
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| Feb24-13, 04:10 PM | #256 |
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Implications of the statement "Acceleration is not relative" |
| Feb24-13, 10:54 PM | #257 |
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[itex]m \dfrac{dV^\mu}{d \tau} = F^\mu[/itex] where [itex]V^\mu[/itex] is the 4-velocity. When you use noninertial or curvilinear coordinates, the relationship between applied force and coordinate acceleration is more complicated: [itex]m \dfrac{dV^\mu}{d \tau} +[/itex]fictitious force terms [itex]= F^\mu[/itex] So even when the applied force [itex]F^\mu[/itex] is zero, the coordinate acceleration [itex]\dfrac{dV^\mu}{d \tau}[/itex] can be nonzero due to "fictitious force" terms. Examples of such fictitious forces are the "g forces" due to acceleration, the "centrifugal force" and the "coriolis force". These "forces" are not due to any kind of physical interaction, but are artifacts of your choice of coordinate systems. |
| Feb25-13, 02:12 AM | #258 |
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| Feb25-13, 02:19 AM | #259 |
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SR doesn't predict that an accelerometer in free fall will indicate a large acceleration. If you insist in this thread instead of starting it as a topic, I'll start that topic for you.
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| Feb25-13, 02:34 AM | #260 |
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| Feb25-13, 03:04 AM | #261 |
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| Feb25-13, 06:34 AM | #262 |
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Yes, SR does predict that. According to SR the proper acceleration is:[tex]a^{\mu}=\frac{d^2x^{\mu}}{d\tau^2}[/tex]Where x is the worldline in an inertial frame and τ is the proper time along that worldline. That quantity is non-zero. |
| Feb25-13, 06:40 AM | #263 |
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| Feb25-13, 06:56 AM | #264 |
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| Feb25-13, 07:01 AM | #265 |
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| Feb25-13, 07:15 AM | #266 |
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Promised thread started here: http://www.physicsforums.com/showthread.php?p=4284966 |
| Feb25-13, 07:25 AM | #267 |
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| Feb25-13, 07:30 AM | #268 |
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| Feb25-13, 12:43 PM | #269 |
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| Feb26-13, 03:21 AM | #270 |
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- http://en.wikisource.org/wiki/The_Fo...ity-postulate. |
| Feb26-13, 06:45 AM | #271 |
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I can't find an online reference to the original argument, but I remember reading it once, and it seemed that Einstein talked about freefall as not the absence of any forces, but as an exact balance between gravitational forces and inertial forces so that they cancel. From the standpoint of today, that seems like a convoluted way of describing it. |
| Feb26-13, 08:37 AM | #272 |
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There's no argument about "forces" or "balance of forces" at all; the argument is purely about the man's observations and how they can be accounted for equally well by the "being" pulling on the rope in free space or by the rope suspending the elevator at rest in a gravitational field. This wasn't a discussion of the twin paradox, it was a discussion of the equivalence principle, so I don't know if you were thinking of some other discussion of his; but what you paraphrased doesn't seem like a discussion of the twin paradox either. |
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