time derivative of creation/annhilation operators

pleasehelpmeno

Basically is it possible to take a time derivative of a creation/annhilation operator?

Einj

I think that's not possible. If you are talking about creation and annhilation operators usually found in QFT, they live in the momentum space, so they don't depend on x, but on p. However, I am not sure if in some other circumstances this could be possible.

pleasehelpmeno

yeah so for eample [itex] \frac{d \hat{a}}{dt} [/itex] would =0 if a was the standard QFT annihilation op

HallsofIvy

Saying you cannot take the "time derivative" does NOT mean that derivative is 0. It means that the derivative does not exist at all.

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pleasehelpmeno	time derivative of creation/annhilation operators Tweet Basically is it possible to take a time derivative of a creation/annhilation operator?

Einj	I think that's not possible. If you are talking about creation and annhilation operators usually found in QFT, they live in the momentum space, so they don't depend on x, but on p. However, I am not sure if in some other circumstances this could be possible.

HallsofIvy Recognitions: Gold Member Science Advisor Staff Emeritus	time derivative of creation/annhilation operators Saying you cannot take the "time derivative" does NOT mean that derivative is 0. It means that the derivative does not exist at all.