time derivative of creation/annhilation operators


by pleasehelpmeno
Tags: quantum field theory
pleasehelpmeno
pleasehelpmeno is offline
#1
Feb26-13, 11:27 AM
P: 160
Basically is it possible to take a time derivative of a creation/annhilation operator?
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Einj
Einj is offline
#2
Feb26-13, 12:53 PM
P: 226
I think that's not possible. If you are talking about creation and annhilation operators usually found in QFT, they live in the momentum space, so they don't depend on x, but on p. However, I am not sure if in some other circumstances this could be possible.
pleasehelpmeno
pleasehelpmeno is offline
#3
Feb26-13, 12:56 PM
P: 160
yeah so for eample [itex] \frac{d \hat{a}}{dt} [/itex] would =0 if a was the standard QFT annihilation op

HallsofIvy
HallsofIvy is offline
#4
Feb26-13, 01:46 PM
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PF Gold
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time derivative of creation/annhilation operators


Saying you cannot take the "time derivative" does NOT mean that derivative is 0. It means that the derivative does not exist at all.


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