Register to reply

Time derivative of creation/annhilation operators

by pleasehelpmeno
Tags: quantum field theory
Share this thread:
pleasehelpmeno
#1
Feb26-13, 11:27 AM
P: 160
Basically is it possible to take a time derivative of a creation/annhilation operator?
Phys.Org News Partner Physics news on Phys.org
New approach to form non-equilibrium structures
Nike krypton laser achieves spot in Guinness World Records
Unleashing the power of quantum dot triplets
Einj
#2
Feb26-13, 12:53 PM
P: 305
I think that's not possible. If you are talking about creation and annhilation operators usually found in QFT, they live in the momentum space, so they don't depend on x, but on p. However, I am not sure if in some other circumstances this could be possible.
pleasehelpmeno
#3
Feb26-13, 12:56 PM
P: 160
yeah so for eample [itex] \frac{d \hat{a}}{dt} [/itex] would =0 if a was the standard QFT annihilation op

HallsofIvy
#4
Feb26-13, 01:46 PM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,322
Time derivative of creation/annhilation operators

Saying you cannot take the "time derivative" does NOT mean that derivative is 0. It means that the derivative does not exist at all.


Register to reply

Related Discussions
Creation and Annihilation Operators Quantum Physics 2
Creation/Ann operators acting on <x|p> Quantum Physics 3
Time it takes for a particle creation/annhilation (according to QFT)? High Energy, Nuclear, Particle Physics 1
Creation/annihilation operators Quantum Physics 16
Ask for Help: Is there this creation operators? Atomic, Solid State, Comp. Physics 1