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Dimension - Linear Algebra |
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| Feb20-06, 11:55 PM | #1 |
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Dimension - Linear Algebra
There are these questions in the book that ask us to find the Dimension of a particular space. Do I just find a basis for the space, and then the number of elements in that basis is the dimension for the space? Or is there some trick to finding the dimension? Thanks!
----------- For example, the first one the book asks is: Find the dimension of 2x2 matricies. So a basis for 2x2 matricies is the following set: [tex]\left\{\left(\begin{array}{cc}1&0\\0&0\end{array}\right), \left(\begin{array}{cc}0&1\\0&0\end{array}\right), \left(\begin{array}{cc}0&0\\1&0\end{array}\right), \left(\begin{array}{cc}0&0\\0&1\end{array}\right)\right\}[/tex] And this basis has 4 elements, so the dimension of 2x2 matricies is 4. --------- Is that basically how these problems go? Thanks. |
| Feb21-06, 12:05 AM | #2 |
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| Feb21-06, 02:24 AM | #3 |
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Recognitions:
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Point of order: a basis is by definition linearly independent. You cannot 'find a basis then check for linear dependency'. Find a spanning set then find the maximal number of linearly independent elements in it, either by inspection or by turning it into a matrix question and using row reductions to put it in echelon form.
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