Sound interference


by kahless2005
Tags: interference, sound
kahless2005
kahless2005 is offline
#1
Mar9-06, 08:44 PM
P: 46
Given for the problem:
A speaker sends out two sound waves with equal Amplitudes but the frequencies are f(1) and f(2) respectively. The motion of sound as w = A * cos(k*x - t*(Omega)). The wave number's and the angular frequency's definition are the same for light.

Find for the problem:
Show that at a distance x directly in front of the speaker, there is destructive interference between the waves with a frequency f(1) - f(2).

My solution so far:
w(1) = A * cos((2PI/(Lambda(1))) * x - (2PI * f(1) * t)
w(2) = A * cos((2PI/(Lambda(2))) * x - (2PI * f(2) * t)

I assume that the final equation will be in the form of:
dt = (x / v) - t
where v is the speed of sound

A little advice please!
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kahless2005
kahless2005 is offline
#2
Mar9-06, 10:53 PM
P: 46
I hope i put this in the right section... It is a Sophmre level physics class...
topsquark
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#3
Mar10-06, 07:09 AM
P: 335
Quote Quote by kahless2005
Given for the problem:
A speaker sends out two sound waves with equal Amplitudes but the frequencies are f(1) and f(2) respectively. The motion of sound as w = A * cos(k*x - t*(Omega)). The wave number's and the angular frequency's definition are the same for light.

Find for the problem:
Show that at a distance x directly in front of the speaker, there is destructive interference between the waves with a frequency f(1) - f(2).

My solution so far:
w(1) = A * cos((2PI/(Lambda(1))) * x - (2PI * f(1) * t)
w(2) = A * cos((2PI/(Lambda(2))) * x - (2PI * f(2) * t)

I assume that the final equation will be in the form of:
dt = (x / v) - t
where v is the speed of sound

A little advice please!
Hint: You are looking for a point, x, where the two waves are out of phase by pi radians.

-Dan

lightgrav
lightgrav is offline
#4
Mar10-06, 11:29 PM
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P: 1,123

Sound interference


"Destructive Interference" in this case is time-dependent cancellation of the total amplitude (that means add the wave functions), at any location.
This is in contrast to location-dependent cancellation of the total amplitude
(an interference pattern) at all time.

Choose an x-value, and add the wave forms ; see when (time) they cancel.


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