# Sound interference

by kahless2005
Tags: interference, sound
 P: 46 Given for the problem: A speaker sends out two sound waves with equal Amplitudes but the frequencies are f(1) and f(2) respectively. The motion of sound as w = A * cos(k*x - t*(Omega)). The wave number's and the angular frequency's definition are the same for light. Find for the problem: Show that at a distance x directly in front of the speaker, there is destructive interference between the waves with a frequency f(1) - f(2). My solution so far: w(1) = A * cos((2PI/(Lambda(1))) * x - (2PI * f(1) * t) w(2) = A * cos((2PI/(Lambda(2))) * x - (2PI * f(2) * t) I assume that the final equation will be in the form of: dt = (x / v) - t where v is the speed of sound A little advice please!
 P: 46 I hope i put this in the right section... It is a Sophmre level physics class...
P: 335
 Quote by kahless2005 Given for the problem: A speaker sends out two sound waves with equal Amplitudes but the frequencies are f(1) and f(2) respectively. The motion of sound as w = A * cos(k*x - t*(Omega)). The wave number's and the angular frequency's definition are the same for light. Find for the problem: Show that at a distance x directly in front of the speaker, there is destructive interference between the waves with a frequency f(1) - f(2). My solution so far: w(1) = A * cos((2PI/(Lambda(1))) * x - (2PI * f(1) * t) w(2) = A * cos((2PI/(Lambda(2))) * x - (2PI * f(2) * t) I assume that the final equation will be in the form of: dt = (x / v) - t where v is the speed of sound A little advice please!
Hint: You are looking for a point, x, where the two waves are out of phase by pi radians.

-Dan

HW Helper
P: 961

## Sound interference

"Destructive Interference" in this case is time-dependent cancellation of the total amplitude (that means add the wave functions), at any location.
This is in contrast to location-dependent cancellation of the total amplitude
(an interference pattern) at all time.

Choose an x-value, and add the wave forms ; see when (time) they cancel.

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